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2^(x)=x+2

2x=x+2 2^{x}=x+2

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Q. 2x=x+2 2^{x}=x+2
  1. Identify Equation Type: Identify the type of equation.\newlineThe equation 2x=x+22^x = x + 2 is a transcendental equation because it involves an exponential function and a polynomial function. There is no algebraic method to solve this type of equation directly. We will attempt to find a solution by inspection or simple substitution.
  2. Check Obvious Solutions: Check for obvious solutions.\newlineWe can check if small integer values of xx satisfy the equation. Let's start with x=0x = 0.\newline20=0+22^0 = 0 + 2\newline1=21 = 2\newlineThis is not true, so x=0x = 0 is not a solution.
  3. Check x=1x = 1: Check the next integer value for xx. Let's try x=1x = 1. 21=1+22^1 = 1 + 2 2=32 = 3 This is also not true, so x=1x = 1 is not a solution.
  4. Check x=2x = 2: Check the next integer value for xx. Let's try x=2x = 2. 22=2+22^2 = 2 + 2 4=44 = 4 This is true, so x=2x = 2 is a solution.

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