Solve the equation. 2(8^(2)-9x)=4(3x+5)

Expand Left Side: Expand the left side of the equation using the distributive property. 2(8^2 - 9x) = 2(64 - 9x) = 2 * 64 - 2 * 9x = 128 - 18xExpand Right Side: Expand the right side of the equation using the distributive property. 4(3x + 5) = 4 * 3x + 4 * 5 = 12x + 20Write Expanded Form: Write the expanded form of both sides of the equation from Step 1 and Step 2. 128 - 18x = 12x + 20Move Terms: Move all terms involving x to one side of the equation and constants to the other side. Add 18x to both sides to move the x terms to the right side: 128 - 18x + 18x = 12x + 18x + 20 128 = 30x + 20Subtract Constant: Subtract 20 from both sides to isolate the term with x. 128 - 20 = 30x + 20 - 20 108 = 30xDivide to Solve: Divide both sides by 30 to solve for x. 108 / 30 = 30x / 30 3.6 = x

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Algebra 2

Add, subtract, multiply, and divide polynomials

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Q. Solve the equation.

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2\left(8^{2}-9 x\right)=4(3 x+5)

Expand Left Side: Expand the left side of the equation using the distributive property. $\newline$ $2(8^2 - 9x) = 2(64 - 9x)$ $\newline$ $= 2 \times 64 - 2 \times 9x$ $\newline$ $= 128 - 18x$
Expand Right Side: Expand the right side of the equation using the distributive property. $\newline$ $4(3x + 5) = 4 \times 3x + 4 \times 5$ $\newline$ $= 12x + 20$
Write Expanded Form: Write the expanded form of both sides of the equation from Step $1$ and Step $2$ . $128 - 18x = 12x + 20$
Move Terms: Move all terms involving $x$ to one side of the equation and constants to the other side. $\newline$ Add $18x$ to both sides to move the $x$ terms to the right side: $\newline$ $128 - 18x + 18x = 12x + 18x + 20$ $\newline$ $128 = 30x + 20$
Subtract Constant: Subtract $20$ from both sides to isolate the term with $x$ . $\newline$ $128 - 20 = 30x + 20 - 20$ $\newline$ $108 = 30x$
Divide to Solve: Divide both sides by $30$ to solve for $x$ . $\newline$ $\frac{108}{30} = \frac{30x}{30}$ $\newline$ $3.6 = x$