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12*(-3i-4)= Your answer should be a complex number in the form a+bi where a and b are real numbers.

12⋅(−3i−4)= 12 \cdot(-3 i-4)= \newlineYour answer should be a complex number in the form a+bi a+b i where a a and b b are real numbers.

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Q. 12⋅(−3i−4)= 12 \cdot(-3 i-4)= \newlineYour answer should be a complex number in the form a+bi a+b i where a a and b b are real numbers.
  1. Multiply real part by 1212: Multiply the real part of the complex number by 1212.\newlineWe have the real part of the complex number as -4＂). Multiplying this by 12 gives us:\(\newline\$12 \times (-4) = -48\)
  2. Multiply imaginary part by \(12\): Multiply the imaginary part of the complex number by \(12\).\(\newline\)The imaginary part of the complex number is \(\(-3\)i＂). Multiplying this by \(12\) gives us:\(\newline\)\(\(12\) \times (\(-3\)i) = \(-36\)i＂)
  3. Combine results for final answer: Combine the results from Step \(1\) and Step \(2\) to get the final answer.\(\newline\)The real part from Step \(1\) is \(-48\) and the imaginary part from Step \(2\) is \(-36i\). Combining these, we get:\(\newline\)\(-48 - 36i\)\(\newline\)This is the final answer in the form \(a + bi\), where \(a\) is the real part and \(b\) is the coefficient of the imaginary part.

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