If 3x^(2)-18 x-15=0, what is the value of x^(2)-6x ? ◻

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Factor Quadratic Equation: Solve the given quadratic equation for x. The given equation is 3x^2 - 18x - 15 = 0. To solve for x, we can either factor the quadratic, complete the square, or use the quadratic formula. Let's try to factor it first.Find Roots: Factor the quadratic equation. We look for two numbers that multiply to (3 * -15) = -45 and add up to -18. These numbers are -15 and -3. So we can write the equation as 3x^2 - 15x - 3x - 15 = 0. Grouping the terms, we get (3x^2 - 15x) - (3x + 15) = 0. Factoring out the common factors, we get 3x(x - 5) - 3(x + 5) = 0. Taking out 3 as a common factor, we get 3(x - 5)(x + 5) = 0.Substitute Roots: Find the roots of the equation. Setting each factor equal to zero gives us the possible solutions for x: x - 5 = 0 or x + 5 = 0. Therefore, x = 5 or x = -5.Verify Solutions: Substitute the roots into the expression x^2 - 6x. We need to find the value of x^2 - 6x for each root and see if they are equal since the question does not specify which root to use.  For x = 5: (5)^2 - 6(5) = 25 - 30 = -5.  For x = -5: (-5)^2 - 6(-5) = 25 + 30 = 55.  The values are not the same, which means we need to check the original equation to see if both roots are valid.Verify the roots in the original equation. For x = 5: 3(5)^2 - 18(5) - 15 = 3(25) - 90 - 15 = 75 - 90 - 15 = -30 - 15 = -45, which is not equal to 0. This means x = 5 is not a valid solution.  For x = -5: 3(-5)^2 - 18(-5) - 15 = 3(25) + 90 - 15 = 75 + 90 - 15 = 165 - 15 = 150, which is not equal to 0. This means x = -5 is not a valid solution either.  There seems to be a mistake in our calculations or in the factoring process. We need to re-evaluate our steps to find the error.

If $3 x^{2}-18 x-15=0$ , what is the value of $x^{2}-6 x$ ? $\newline$ $\square$

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If 3x2−18x−15=0 3 x^{2}-18 x-15=0 3x2−18x−15=0, what is the value of x2−6x x^{2}-6 x x2−6x ?\newline□ \square □

If $3 x^{2}-18 x-15=0$ , what is the value of $x^{2}-6 x$ ? $\newline$ $\square$