119 is a root of f(x)=x2+14,161. Find the other roots of f(x).Write your answer as a list of simplified values separated by commas, if there is more than one value.
Q. 119 is a root of f(x)=x2+14,161. Find the other roots of f(x).Write your answer as a list of simplified values separated by commas, if there is more than one value.
Write as x−119: Since 119 is a root, we can write it as x−119=0. Now we need to find the other root by factoring the polynomial.f(x)=x2+14,161 can be rewritten as f(x)=(x−119)(x−a) where a is the other root we need to find.
Find other root: To find the value of a, we expand the factored form and compare coefficients.(x−119)(x−a)=x2−(119+a)x+119aThe constant term in the polynomial f(x) is 14,161, so we set 119a equal to 14,161.
Expand and compare coefficients: Solving for 'a', we divide 14,161 by 119. a=11914,161a=119