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0.5(8w+2v)=3

8w=2-v+4w
Which of the following accurately describes all solutions to the system of equations shown?
Choose 1 answer:
(A) 
v=1 and 
w=(1)/(4)
(B) 
v=4 and 
w=-(1)/(4)
(C) There are infinite solutions to the system.
(D) There are no solutions to the system.

0.5(8w+2v)=30.5(8w+2v)=3\newline8w=2v+4w8w=2-v+4w\newlineWhich of the following accurately describes all solutions to the system of equations shown?\newlineChoose 11 answer:\newline(A) v=1v=1 and w=14w=\frac{1}{4}\newline(B) v=4v=4 and w=14w=-\frac{1}{4}\newline(C) There are infinite solutions to the system.\newline(D) There are no solutions to the system.

Full solution

Q. 0.5(8w+2v)=30.5(8w+2v)=3\newline8w=2v+4w8w=2-v+4w\newlineWhich of the following accurately describes all solutions to the system of equations shown?\newlineChoose 11 answer:\newline(A) v=1v=1 and w=14w=\frac{1}{4}\newline(B) v=4v=4 and w=14w=-\frac{1}{4}\newline(C) There are infinite solutions to the system.\newline(D) There are no solutions to the system.
  1. Simplify Equation: Simplify the first equation.\newlineGiven: 0.5(8w+2v)=30.5(8w+2v)=3\newlineMultiply both sides by 22 to eliminate the fraction: 8w+2v=68w + 2v = 6
  2. Isolate Variable: Isolate the variable ww in the second equation.\newlineGiven: 8w=2v+4w8w = 2 - v + 4w\newlineSubtract 4w4w from both sides to get: 4w=2v4w = 2 - v
  3. Solve for w: Solve for w in terms of v.\newlineDivide both sides by 44: w=2v4w = \frac{2 - v}{4}
  4. Substitute in First Equation: Substitute ww from Step 33 into the first equation.\newlineReplace ww in 8w+2v=68w + 2v = 6 with (2v)/4(2 - v)/4: 8((2v)/4)+2v=68((2 - v)/4) + 2v = 6
  5. Simplify Substitution: Simplify the equation.\newlineDistribute 88 into (2v)/4(2 - v)/4: 2(2v)+2v=62(2 - v) + 2v = 6
  6. Expand and Combine: Expand and combine like terms. 42v+2v=64 - 2v + 2v = 6
  7. Check Validity: Check if the equation is valid.\newlineSince 42v+2v4 - 2v + 2v simplifies to 44, we have 4=64 = 6, which is not true.
  8. Determine Solutions: Determine the nature of the solutions.\newlineSince we arrived at a false statement, this implies that there are no values of vv and ww that can satisfy both equations simultaneously. Therefore, there are no solutions to the system.

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