{[y=x-4],[y=4x+2]:} {:[x=],[y=]:}

Set Equations Equal: We have a system of two equations: 1) y = x - 4 2) y = 4x + 2 To find the values of x and y that satisfy both equations, we can set them equal to each other since they both equal y. So, we set x - 4 = 4x + 2.Solve for x: Now we solve for x: x - 4 = 4x + 2 Subtract x from both sides to get: -4 = 3x + 2Isolate x Term: Next, subtract 2 from both sides to isolate the term with x: -4 - 2 = 3x -6 = 3xSolve for x: Now, divide both sides by 3 to solve for x: -6 / 3 = x x = -2Substitute x into Equation: With the value of x found, we can substitute it back into either of the original equations to find y. We'll use the first equation: y = x - 4 y = -2 - 4 y = -6

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$\left\{\begin{array}{l}y=x-4 \\ y=4 x+2\end{array}\right.$ $\newline$ $\begin{array}{l}x= \\ y=\end{array}$

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\left\{\begin{array}{l}y=x-4 \\ y=4 x+2\end{array}\right.

\newline

\begin{array}{l}x= \\ y=\end{array}

Set Equations Equal: We have a system of two equations: $\newline$ $1$ ) $y = x - 4$ $\newline$ $2$ ) $y = 4x + 2$ $\newline$ To find the values of $x$ and $y$ that satisfy both equations, we can set them equal to each other since they both equal $y$ . $\newline$ So, we set $x - 4 = 4x + 2$ .
Solve for x: Now we solve for x: $\newline$ $x - 4 = 4x + 2$ $\newline$ Subtract $x$ from both sides to get: $\newline$ $-4 = 3x + 2$
Isolate x Term: Next, subtract $2$ from both sides to isolate the term with $x$ : $\newline$ $-4 - 2 = 3x$ $\newline$ $-6 = 3x$
Solve for x: Now, divide both sides by $3$ to solve for x: $\newline$ $-6 / 3 = x$ $\newline$ $x = -2$
Substitute $x$ into Equation: With the value of $x$ found, we can substitute it back into either of the original equations to find $y$ . We'll use the first equation: $\newline$ $y = x - 4$ $\newline$ $y = -2 - 4$ $\newline$ $y = -6$