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{:[y=5x+3],[2y=18 x-10]:}

y=5x+32y=18x10 \begin{array}{c}y=5 x+3 \\ 2 y=18 x-10\end{array}

Full solution

Q. y=5x+32y=18x10 \begin{array}{c}y=5 x+3 \\ 2 y=18 x-10\end{array}
  1. Given Equations: We are given a system of linear equations:\newliney=5x+3,2y=18x10{y=5x+3}, {2y=18x-10}\newlineOur goal is to find the values of xx and yy that satisfy both equations simultaneously.
  2. Express yy in terms of xx: First, let's use the first equation to express yy in terms of xx:y=5x+3y = 5x + 3
  3. Substitute into second equation: Now, let's substitute the expression for yy from the first equation into the second equation: 2(5x+3)=18x102(5x + 3) = 18x - 10
  4. Distribute and simplify: Next, we distribute the 22 on the left side of the equation: 2×5x+2×3=18x102 \times 5x + 2 \times 3 = 18x - 10 10x+6=18x1010x + 6 = 18x - 10
  5. Rearrange terms: Now, we'll move all terms involving xx to one side and constant terms to the other side: 10x18x=10610x - 18x = -10 - 6 8x=16-8x = -16
  6. Find xx: To find the value of xx, we divide both sides of the equation by 8-8:x=168x = \frac{{-16}}{{-8}}x=2x = 2
  7. Substitute xx into first equation: Now that we have the value of xx, we can substitute it back into the first equation to find yy:y=5(2)+3y = 5(2) + 3y=10+3y = 10 + 3y=13y = 13