{:[x+y=3],[x-3y=-9]:} What is the solution (x,y) to the given system of equations?

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{:[x+y=3],[x-3y=-9]:} What is the solution  (x,y) to the given system of equations?

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Write Equations: Write down the system of equations. We have the following system of linear equations: 1) x + y = 3 2) x - 3y = -9 We will use the method of elimination or substitution to find the values of x and y.Choose Solution Method: Decide which method to use for solving the system. We can use either elimination or substitution. For this example, let's use the substitution method since the first equation is already solved for x in terms of y.Solve for x: Solve the first equation for x. x = 3 - y Now we have an expression for x that we can substitute into the second equation.Substitute x: Substitute the expression for x into the second equation. Substitute x = 3 - y into x - 3y = -9: (3 - y) - 3y = -9Simplify and Solve for y: Simplify the equation and solve for y. 3 - y - 3y = -9 Combine like terms: 3 - 4y = -9 Now, subtract 3 from both sides: -4y = -9 - 3 -4y = -12 Now, divide both sides by -4 to solve for y: y = -12 / -4 y = 3Substitute y into First Equation: Substitute the value of y back into the first equation to solve for x. Now that we know y = 3, substitute it back into the first equation: x + 3 = 3 Subtract 3 from both sides to solve for x: x = 3 - 3 x = 0Find Solution: Write down the solution to the system of equations. The solution to the system of equations is (x, y) = (0, 3).

$\begin{array}{c} x+y=3 \\ x-3 y=-9 \end{array}$ $\newline$ What is the solution $(x, y)$ to the given system of equations?

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x+y=3x−3y=−9 \begin{array}{c} x+y=3 \\ x-3 y=-9 \end{array} x+y=3x−3y=−9​\newlineWhat is the solution (x,y) (x, y) (x,y) to the given system of equations?

$\begin{array}{c} x+y=3 \\ x-3 y=-9 \end{array}$ $\newline$ What is the solution $(x, y)$ to the given system of equations?