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(x−h)2+(y−k)2=r2(x-h)^2+(y-k)^2=r^2 find yy.

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Full solution

Q. (x−h)2+(y−k)2=r2(x-h)^2+(y-k)^2=r^2 find yy.
  1. Identify equation type: Identify the equation type and isolate yy. We have the equation of a circle: (x−h)2+(y−k)2=r2(x-h)^2 + (y-k)^2 = r^2. To find yy, we need to isolate it. Rearrange the equation: (y−k)2=r2−(x−h)2(y-k)^2 = r^2 - (x-h)^2.
  2. Isolate yy: Solve for yy.\newlineTake the square root on both sides: y−k=±r2−(x−h)2y-k = \pm\sqrt{r^2 - (x-h)^2}.\newlineThen, y=k±r2−(x−h)2y = k \pm \sqrt{r^2 - (x-h)^2}.

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