Expand the expression : (x-3)(x^(2)+3x+9)

Identify Expression: Identify the expression after distributing (x^(2)+3x+9). Distribute (x^(2)+3x+9) to each term of (x-3). (x-3)(x^(2)+3x+9) = x(x^(2)+3x+9) - 3(x^(2)+3x+9)Distribute to Each Term: Simplify x(x^(2)+3x+9). x(x^(2)+3x+9) = x(x^(2)) + x(3x) + x(9) = x^(3) + 3x^(2) + 9xSimplify First Term: Simplify -3(x^(2)+3x+9). -3(x^(2)+3x+9) = -3(x^(2)) - 3(3x) - 3(9) = -3x^(2) - 9x - 27Simplify Second Term: Combine the results from Step 2 and Step 3. x(x^(2)+3x+9) - 3(x^(2)+3x+9) = (x^(3) + 3x^(2) + 9x) - (3x^(2) + 9x + 27) = x^(3) + 3x^(2) + 9x - 3x^(2) - 9x - 27Combine Results: Simplify the expression by combining like terms. x^(3) + 3x^(2) + 9x - 3x^(2) - 9x - 27 = x^(3) + (3x^(2) - 3x^(2)) + (9x - 9x) - 27 = x^(3) - 27

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Expand the expression : (x-3)(x^(2)+3x+9)

Expand the expression : $(x-3)\left(x^{2}+3 x+9\right)$

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Algebra 2

Add, subtract, multiply, and divide polynomials

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Q. Expand the expression :

(x-3)\left(x^{2}+3 x+9\right)

Identify Expression: Identify the expression after distributing $x^{2}+3x+9$ . Distribute $x^{2}+3x+9$ to each term of $x-3$ . $(x-3)(x^{2}+3x+9) = x(x^{2}+3x+9) - 3(x^{2}+3x+9)$
Distribute to Each Term: Simplify $x(x^{2}+3x+9)$ .
$x(x^{2}+3x+9)$
= $x(x^{2}) + x(3x) + x(9)$
= $x^{3} + 3x^{2} + 9x$
Simplify First Term: Simplify $-3(x^{2}+3x+9)$ . $-3(x^{2}+3x+9) = -3(x^{2}) - 3(3x) - 3(9) = -3x^{2} - 9x - 27$
Simplify Second Term: Combine the results from Step $2$ and Step $3$ . $\newline$ x(x^{2}+3x+9) - 3(x^{2}+3x+9) $\newline= (x^{3} + 3x^{2} + 9x) - (3x^{2} + 9x + 27) $\newline$ = x^{3} + 3x^{2} + 9x - 3x^{2} - 9x - 27$
Combine Results: Simplify the expression by combining like terms. $\newline$ $x^{3} + 3x^{2} + 9x - 3x^{2} - 9x - 27$ $\newline$ = $x^{3} + (3x^{2} - 3x^{2}) + (9x - 9x) - 27$ $\newline$ = $x^{3} - 27$