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(x^(3)+x^(2)+3)÷(x+4)

(x3+x2+3)÷(x+4) \left(x^{3}+x^{2}+3\right) \div(x+4)

Full solution

Q. (x3+x2+3)÷(x+4) \left(x^{3}+x^{2}+3\right) \div(x+4)
  1. Use polynomial long division: To divide the polynomial (x3+x2+3)(x^3 + x^2 + 3) by (x+4)(x + 4), we will use polynomial long division.
  2. Divide leading terms: First, we divide the leading term of the numerator, x3x^3, by the leading term of the denominator, xx, to get x2x^2.
  3. Multiply by result: We then multiply the entire denominator (x+4)(x + 4) by this result (x2)(x^2) to get x3+4x2x^3 + 4x^2.
  4. Subtract to find remainder: Next, we subtract the product (x3+4x2)(x^3 + 4x^2) from the original numerator (x3+x2+3)(x^3 + x^2 + 3) to find the new remainder. This gives us (x3+x2+3)(x3+4x2)=3x2+3(x^3 + x^2 + 3) - (x^3 + 4x^2) = -3x^2 + 3.
  5. Divide new remainder: Now, we divide the leading term of the new remainder, 3x2-3x^2, by the leading term of the denominator, xx, to get 3x-3x.
  6. Multiply by 3x-3x: We multiply the entire denominator (x+4)(x + 4) by 3x-3x to get 3x212x-3x^2 - 12x.
  7. Subtract to find next remainder: Subtract this product from the current remainder to find the next remainder. This gives us (3x2+3)(3x212x)=12x+3(-3x^2 + 3) - (-3x^2 - 12x) = 12x + 3.
  8. Divide new remainder: Now, we divide the leading term of the new remainder, 12x12x, by the leading term of the denominator, xx, to get 1212.
  9. Multiply by 1212: We multiply the entire denominator x+4x + 4 by 1212 to get 12x+4812x + 48.
  10. Subtract to find next remainder: Subtract this product from the current remainder to find the next remainder. This gives us (12x+3)(12x+48)=45(12x + 3) - (12x + 48) = -45.
  11. Check for completion: Since the degree of the remainder 45 -45 is less than the degree of the denominator x+4 x + 4 , we cannot continue the division process. The result of the division is the quotient plus the remainder over the original divisor.
  12. Final answer: The quotient we obtained is x23x+12x^2 - 3x + 12, and the remainder is 45-45. Therefore, the final answer is x23x+12x^2 - 3x + 12 with a remainder of 45-45, which can be written as (x23x+12)45x+4(x^2 - 3x + 12) - \frac{45}{x + 4}.

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