Q. x=2y+5y=(2x−3)(x+9)How many ordered pairs (x,y) satisfy the system of equations shown above?A) 0B) 1C) 2D) Infinitely many
Understand the Equations: Understand the system of equations.We have a system of two equations:1) x=2y+52) y=(2x−3)(x+9)We need to find the number of ordered pairs (x,y) that satisfy both equations simultaneously.
Substitute and Solve: Substitute the expression for x from the first equation into the second equation.From equation 1, we have x=2y+5. We can substitute this into equation 2 in place of x to solve for y.y=(2(2y+5)−3)((2y+5)+9)
Simplify the Expression: Simplify the equation obtained after substitution.y=(4y+10−3)(2y+14)y=(4y+7)(2y+14)Now, we will expand this to get a quadratic equation in terms of y.
Expand and Simplify: Expand the equation and simplify.y=(4y+7)(2y+14)y=8y2+28y+14y+98y=8y2+42y+98
Set Equation to Zero: Move all terms to one side to set the equation to zero.0=8y2+42y+98−y0=8y2+41y+98
Factor Quadratic Equation: Factor the quadratic equation, if possible.We need to factor 8y2+41y+98. However, this does not factor nicely, and we may need to use the quadratic formula to find the roots.
Use Quadratic Formula: Use the quadratic formula to find the roots of the equation.The quadratic formula is y=2a−b±b2−4ac, where a=8, b=41, and c=98.Discriminant = b2−4ac=412−4(8)(98)Discriminant = 1681−3136Discriminant = −1455
Analyzing the Discriminant: Analyze the discriminant.Since the discriminant is negative (−1455), there are no real solutions for y. This means there are no ordered pairs (x,y) that satisfy the system of equations.