Distribute first binomial: Now, we will multiply the result (x^2 - 6x - 7) by the third binomial (x+3). We distribute each term of (x+3) to each term of (x^2 - 6x - 7). (x^2 - 6x - 7)(x + 3) = x^2(x) + x^2(3) - 6x(x) - 6x(3) - 7(x) - 7(3) = x^3 + 3x^2 - 6x^2 - 18x - 7x - 21Combine like terms: Next, we combine like terms in the expression. x^3 + 3x^2 - 6x^2 - 18x - 7x - 21 = x^3 - 3x^2 - 25x - 21

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$(x+1)(x-7)(x+3)$

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Algebra 2

Add, subtract, multiply, and divide polynomials

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(x+1)(x-7)(x+3)

Distribute first binomial: Now, we will multiply the result $(x^2 - 6x - 7)$ by the third binomial $(x+3)$ . We distribute each term of $(x+3)$ to each term of $(x^2 - 6x - 7)$ . $(x^2 - 6x - 7)(x + 3) = x^2(x) + x^2(3) - 6x(x) - 6x(3) - 7(x) - 7(3)$ $= x^3 + 3x^2 - 6x^2 - 18x - 7x - 21$
Combine like terms: Next, we combine like terms in the expression. $\newline$ $x^3 + 3x^2 - 6x^2 - 18x - 7x - 21$ $\newline$ = $x^3 - 3x^2 - 25x - 21$