Write the formula of trigonometric ratio of cos(270^(@)-A).

Recognize Trigonometric Identity: Recognize the trigonometric identity for cosine of a difference. The formula for the cosine of the difference of two angles is cos(α - β) = cos(α)cos(β) + sin(α)sin(β). However, in this case, we are dealing with a specific angle, 270°, which is a special angle in trigonometry. We need to use the fact that cos(270°) = 0 and sin(270°) = -1.Apply Identity to 270°: Apply the cosine difference identity to the specific angle 270°. Using the identity from Step 1, we substitute α with 270° and β with A to get cos(270° - A) = cos(270°)cos(A) + sin(270°)sin(A).Substitute Known Values: Substitute the known values of cos(270°) and sin(270°) into the equation. We know that cos(270°) = 0 and sin(270°) = -1, so we substitute these values into the equation from Step 2 to get cos(270° - A) = (0)cos(A) + (-1)sin(A).Simplify Equation: Simplify the equation. Since (0)cos(A) is 0, it drops out of the equation, and we are left with cos(270° - A) = -sin(A).

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Write the formula of trigonometric ratio of
cos(270^(@)-A).

Write the formula of trigonometric ratio of $\cos \left(270^{\circ}-\mathrm{A}\right)$

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Q. Write the formula of trigonometric ratio of

\cos \left(270^{\circ}-\mathrm{A}\right)

Recognize Trigonometric Identity: Recognize the trigonometric identity for cosine of a difference. The formula for the cosine of the difference of two angles is $\cos(\alpha - \beta) = \cos(\alpha)\cos(\beta) + \sin(\alpha)\sin(\beta)$ . However, in this case, we are dealing with a specific angle, $270^\circ$ , which is a special angle in trigonometry. We need to use the fact that $\cos(270^\circ) = 0$ and $\sin(270^\circ) = -1$ .
Apply Identity to $270°$ : Apply the cosine difference identity to the specific angle $270°$ . Using the identity from Step $1$ , we substitute $\alpha$ with $270°$ and $\beta$ with $A$ to get $\cos(270° - A) = \cos(270°)\cos(A) + \sin(270°)\sin(A)$ .
Substitute Known Values: Substitute the known values of $\cos(270°)$ and $\sin(270°)$ into the equation. $\newline$ We know that $\cos(270°) = 0$ and $\sin(270°) = -1$ , so we substitute these values into the equation from Step $2$ to get $\cos(270° - A) = (0)\cos(A) + (-1)\sin(A)$ .
Simplify Equation: Simplify the equation. $\newline$ Since $(0)\cos(A)$ is $0$ , it drops out of the equation, and we are left with $\cos(270° - A) = -\sin(A)$ .