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(iii)
6
(
8
)
n
+
1
+
16
(
2
)
3
n
−
2
10
(
2
)
3
n
+
1
−
7
(
8
)
n
\frac{6(8)^{n+1}+16(2)^{3 n-2}}{10(2)^{3 n+1}-7(8)^{n}}
10
(
2
)
3
n
+
1
−
7
(
8
)
n
6
(
8
)
n
+
1
+
16
(
2
)
3
n
−
2
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Home
Math Problems
Algebra 2
Add, subtract, multiply, and divide polynomials
Full solution
Q.
(iii)
6
(
8
)
n
+
1
+
16
(
2
)
3
n
−
2
10
(
2
)
3
n
+
1
−
7
(
8
)
n
\frac{6(8)^{n+1}+16(2)^{3 n-2}}{10(2)^{3 n+1}-7(8)^{n}}
10
(
2
)
3
n
+
1
−
7
(
8
)
n
6
(
8
)
n
+
1
+
16
(
2
)
3
n
−
2
Simplify terms involving powers:
First, simplify the terms involving powers of
8
8
8
and
2
2
2
.
(
6
(
8
)
(
n
+
1
)
=
6
×
8
×
8
n
=
48
×
8
n
,
(6(8)^{(n+1)} = 6 \times 8 \times 8^n = 48 \times 8^n,
(
6
(
8
)
(
n
+
1
)
=
6
×
8
×
8
n
=
48
×
8
n
,
16
(
2
)
(
3
n
−
2
)
=
16
×
2
(
3
n
−
2
)
,
16(2)^{(3n-2)} = 16 \times 2^{(3n-2)},
16
(
2
)
(
3
n
−
2
)
=
16
×
2
(
3
n
−
2
)
,
10
(
2
)
(
3
n
+
1
)
=
10
×
2
×
2
(
3
n
)
=
20
×
2
(
3
n
)
,
10(2)^{(3n+1)} = 10 \times 2 \times 2^{(3n)} = 20 \times 2^{(3n)},
10
(
2
)
(
3
n
+
1
)
=
10
×
2
×
2
(
3
n
)
=
20
×
2
(
3
n
)
,
7
(
8
)
(
n
)
=
7
×
8
n
.
7(8)^{(n)} = 7 \times 8^n.
7
(
8
)
(
n
)
=
7
×
8
n
.
Rewrite using simplified terms:
Rewrite the expression using simplified terms:
(
48
⋅
8
n
+
16
⋅
2
3
n
−
2
)
/
(
20
⋅
2
3
n
−
7
⋅
8
n
)
(48 \cdot 8^n + 16 \cdot 2^{3n-2}) / (20 \cdot 2^{3n} - 7 \cdot 8^n)
(
48
⋅
8
n
+
16
⋅
2
3
n
−
2
)
/
(
20
⋅
2
3
n
−
7
⋅
8
n
)
.
Recognize and substitute:
Recognize that
8
n
=
(
2
3
)
n
=
2
3
n
8^n = (2^3)^n = 2^{3n}
8
n
=
(
2
3
)
n
=
2
3
n
and substitute:
\newline
(
48
⋅
2
3
n
+
16
⋅
2
3
n
−
2
)
/
(
20
⋅
2
3
n
−
7
⋅
2
3
n
)
(48 \cdot 2^{3n} + 16 \cdot 2^{3n-2}) / (20 \cdot 2^{3n} - 7 \cdot 2^{3n})
(
48
⋅
2
3
n
+
16
⋅
2
3
n
−
2
)
/
(
20
⋅
2
3
n
−
7
⋅
2
3
n
)
.
Factor out common terms:
Factor out common terms in the numerator and denominator:
\newline
2
3
n
−
2
×
(
48
×
4
+
16
)
/
2
3
n
×
(
20
−
7
)
2^{3n-2} \times (48 \times 4 + 16) / 2^{3n} \times (20 - 7)
2
3
n
−
2
×
(
48
×
4
+
16
)
/
2
3
n
×
(
20
−
7
)
,
\newline
=
2
3
n
−
2
×
(
192
+
16
)
/
2
3
n
×
13
= 2^{3n-2} \times (192 + 16) / 2^{3n} \times 13
=
2
3
n
−
2
×
(
192
+
16
)
/
2
3
n
×
13
,
\newline
=
2
3
n
−
2
×
208
/
2
3
n
×
13
= 2^{3n-2} \times 208 / 2^{3n} \times 13
=
2
3
n
−
2
×
208/
2
3
n
×
13
.
Reduce powers of
2
2
2
:
Simplify by reducing the powers of
2
2
2
:
\newline
2
3
n
−
2
/
2
3
n
=
2
−
2
2^{3n-2} / 2^{3n} = 2^{-2}
2
3
n
−
2
/
2
3
n
=
2
−
2
,
\newline
=
2
−
2
×
208
/
13
= 2^{-2} \times 208 / 13
=
2
−
2
×
208/13
,
\newline
=
208
/
(
13
×
4
)
= 208 / (13 \times 4)
=
208/
(
13
×
4
)
,
\newline
=
208
/
52
= 208 / 52
=
208/52
.
Perform division:
Perform the division:
208
/
52
=
4
208 / 52 = 4
208/52
=
4
.
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(
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(
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)
=
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−
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)
(
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