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{:[{[h(1)=9],[h(2)=3],[h(n)=h(n-2)*h(n-1)]:}],[h(3)=◻]:}

{h(1)=9h(2)=3h(n)=h(n2)h(n1)h(3)= \begin{array}{l}\left\{\begin{array}{l}h(1)=9 \\ h(2)=3 \\ h(n)=h(n-2) \cdot h(n-1)\end{array}\right. \\ h(3)=\square\end{array}

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