{:[g(t)=-9t-4],[g(◻)=23]:}

Set g(t) equal to 23: Set the function g(t) equal to 23. g(t) = -9t - 4 23 = -9t - 4 Add 4 to isolate t: Add 4 to both sides of the equation to isolate the term containing t. 23 + 4 = -9t - 4 + 4 27 = -9t Divide by -9 to solve for t: Divide both sides of the equation by -9 to solve for t. 27 / -9 = -9t / -9 -3 = t

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$\begin{array}{l}g(t)=-9 t-4 \\ g(\square)=23\end{array}$

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Grade 6

Multiply two decimals: where does the decimal point go?

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\begin{array}{l}g(t)=-9 t-4 \\ g(\square)=23\end{array}

Set $g(t)$ equal to $23$ : Set the function $g(t)$ equal to $23$ .
$g(t) = -9t - 4$
$23 = -9t - 4$
Add $4$ to isolate t: Add $4$ to both sides of the equation to isolate the term containing t. $\newline$ $23 + 4 = -9t - 4 + 4$ $\newline$ $27 = -9t$
Divide by ext{-} $9$ to solve for t: Divide both sides of the equation by ext{-} $9$ to solve for t. $\newline$ $\frac{27}{-9} = \frac{-9t}{-9}$ $\newline$ $-3 = t$