{:[f(t)=5t-7],[f(◻)=48]:}

Write Function and Value: Write down the given function and the value for f(t). We are given the function f(t) = 5t - 7 and we need to find the value of t when f(t) = 48.Set Up Equation: Set up the equation using the given value for f(t). We need to solve the equation 5t - 7 = 48.Add 7 to Isolate: Add 7 to both sides of the equation to isolate the term with t. 5t - 7 + 7 = 48 + 7 This simplifies to 5t = 55.Divide to Solve: Divide both sides of the equation by 5 to solve for t. 5t / 5 = 55 / 5 This simplifies to t = 11.

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$\begin{array}{l}f(t)=5 t-7 \\ f(\square)=48\end{array}$

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Grade 6

Multiply two decimals: where does the decimal point go?

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\begin{array}{l}f(t)=5 t-7 \\ f(\square)=48\end{array}

Write Function and Value: Write down the given function and the value for $f(t)$ . We are given the function $f(t) = 5t - 7$ and we need to find the value of $t$ when $f(t) = 48$ .
Set Up Equation: Set up the equation using the given value for $f(t)$ . We need to solve the equation $5t - 7 = 48$ .
Add $7$ to Isolate: Add $7$ to both sides of the equation to isolate the term with $t$ . $\newline$ $5t - 7 + 7 = 48 + 7$ $\newline$ This simplifies to $5t = 55$ .
Divide to Solve: Divide both sides of the equation by $5$ to solve for $t$ . $\newline$ $\frac{5t}{5} = \frac{55}{5}$ $\newline$ This simplifies to $t = 11$ .