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j2+7=12\dfrac{j}{2}+ 7= 12 What is the value of jj in the equation shown?

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Positive and negative square rootsright chevron icon

Full solution

Q. j2+7=12\dfrac{j}{2}+ 7= 12 What is the value of jj in the equation shown?
  1. Subtract 77 to isolate j: Subtract 77 from both sides to isolate the term with j.\newlinej2+7−7=12−7\frac{j}{2} + 7 - 7 = 12 - 7\newlinej2=5\frac{j}{2} = 5
  2. Multiply by 22 to solve: Multiply both sides by 22 to solve for j.\newlinej2×2=5×2\frac{j}{2} \times 2 = 5 \times 2\newlinej=10j = 10

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