Q. (ax+5)(x+v)=ax2+25x+25What is the value of a in the given equation?Choose 1 answer:(A) −5(B) −4(C) 4(D) 5
Expand Left Side: Expand the left side of the equation (ax+5)(x+v) using the distributive property (FOIL method).(ax+5)(x+v)=ax⋅x+ax⋅v+5⋅x+5⋅v
Compare with Right Side: Compare the expanded form with the right side of the equation ax2+25x+25. We have ax×x=ax2, which is already in the correct form. Now, we need to find the terms that combine to give us 25x on the right side.
Find Terms for 25x: The terms ax∗v and 5∗x must add up to 25x.So, ax∗v+5∗x=25x.
Deduce Value of v: Since there is no x term on the left side that would correspond to 25x on the right side, we can deduce that v must be 5 to satisfy the equation.This is because 5×x is already part of the 25x term on the right side, so ax×v must be the remaining 20x.
Simplify Equation: Now we have ax×5+5×x=20x+5x=25x. This simplifies to 5a×x+5×x=25x.
Divide and Solve for a: Divide the entire equation by x to simplify and solve for a.5a+5=25.
Subtract to Isolate a: Subtract 5 from both sides to isolate the term with a.5a=25−5.
Calculate Value of a: Calculate the value of a.5a=20.a=520.a=4.
Final Answer: The value of a is 4, which corresponds to option (C).
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