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(a) Does 
(2,-2) satisfy the equation 
(3)/(2)x+y-4=0 ?
No
Yes

(a) Does (2,2) (2,-2) satisfy the equation 32x+y4=0 \frac{3}{2} x+y-4=0 ?\newlineNo\newlineYes

Full solution

Q. (a) Does (2,2) (2,-2) satisfy the equation 32x+y4=0 \frac{3}{2} x+y-4=0 ?\newlineNo\newlineYes
  1. Identify values of xx and yy: Identify the values of xx and yy in the point (2,2)(2, -2). We have x=2x = 2 and y=2y = -2.
  2. Substitute values into equation: Substitute the values of xx and yy into the equation 32x+y4=0\frac{3}{2}x + y - 4 = 0. Substitute 22 for xx and 2-2 for yy into the equation. Calculation: 322+(2)4=0\frac{3}{2}\cdot2 + (-2) - 4 = 0
  3. Perform multiplication and addition: Perform the multiplication and addition to simplify the equation.\newlineCalculation: 3+(2)4=03 + (-2) - 4 = 0
  4. Combine numbers to check equation: Combine the numbers to see if the equation is satisfied.\newlineCalculation: 324=33 - 2 - 4 = -3
  5. Determine if equation is satisfied: Determine if the simplified equation equals zero.\newline30-3 \neq 0, so the point (2,2)(2, -2) does not satisfy the equation 32x+y4=0\frac{3}{2}x + y - 4 = 0.

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