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{:[6x-2y=10],[3x-y=2]:}

6x2y=103xy=2 \begin{array}{l} 6 x-2 y=10 \\ 3 x-y=2 \\\end{array}

Full solution

Q. 6x2y=103xy=2 \begin{array}{l} 6 x-2 y=10 \\ 3 x-y=2 \\\end{array}
  1. Write Equations: Write down the system of equations.\newlineWe have the following system of equations:\newline6x2y=106x - 2y = 10 ...(11)\newline3xy=23x - y = 2 ...(22)\newlineWe need to find the values of xx and yy that satisfy both equations simultaneously.
  2. Solve for yy: Solve the second equation for yy. From equation (22), we can express yy in terms of xx: 3xy=23x - y = 2 y=3x2y = 3x - 2 ...(33) This gives us yy in terms of xx, which we can use to substitute into the first equation.
  3. Substitute and Simplify: Substitute the expression for yy from equation (33) into equation (11).\newlineSubstituting y=3x2y = 3x - 2 into equation (11) gives us:\newline6x2(3x2)=106x - 2(3x - 2) = 10\newlineNow we need to simplify and solve for xx.
  4. Identify Contradiction: Simplify the equation and solve for xx.6x2(3x2)=106x - 2(3x - 2) = 106x6x+4=106x - 6x + 4 = 10The terms 6x6x and 6x-6x cancel each other out, so we are left with:4=104 = 10This is a contradiction, which means there is an error in our calculations or the system of equations does not have a solution.