-(a-1)(b-1)(c-1) Which of the following is equivalent to the given expression? Choose 1 answer: (A) (1-a)(b-1)(1-c) (B) (1-a)(1-b)(1-c) (C) (a-1)(1-b)(1-c) (D) (1-a)(1-b)(c-1)

Distribute Negative Sign: Distribute the negative sign across the expression. We need to distribute the negative sign to each term within the parentheses. This will change the sign of each term inside the parentheses. -(a-1)(b-1)(c-1) = (-1)*(a-1)(b-1)(c-1) Now, distribute the -1 to each term inside the first set of parentheses. (-1)*(a-1) = (1-a)Apply Distribution: Apply the distributed negative sign to the other terms. Now, we apply the same logic to the other two sets of parentheses. (-1)*(b-1) = (1-b) (-1)*(c-1) = (1-c)Combine Results: Combine the results from Step 1 and Step 2. Now we combine the results of distributing the negative sign to each term. (1-a)(1-b)(1-c)Match with Options: Match the result with the given options. The expression we have obtained is (1-a)(1-b)(1-c), which matches option (B).

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$- (a - 1)(b - 1)(c - 1)$ $\newline$ Which of the following is equivalent to the given expression? $\newline$ Choose $1$ answer: $\newline$ (A) $(1 - a)(b - 1)(1 - c)$ $\newline$ (B) $(1 - a)(1 - b)(1 - c)$ $\newline$ (C) $(a - 1)(1 - b)(1 - c)$ $\newline$ (D) $(1 - a)(1 - b)(c - 1)$

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Math Problems

Algebra 2

Solve quadratic inequalities

Full solution

- (a - 1)(b - 1)(c - 1)

\newline

Which of the following is equivalent to the given expression?

\newline

Choose

1

answer:

\newline

(A)

(1 - a)(b - 1)(1 - c)

\newline

(B)

(1 - a)(1 - b)(1 - c)

\newline

(C)

(a - 1)(1 - b)(1 - c)

\newline

(D)

(1 - a)(1 - b)(c - 1)

Distribute Negative Sign: Distribute the negative sign across the expression. $\newline$ We need to distribute the negative sign to each term within the parentheses. This will change the sign of each term inside the parentheses. $\newline$ $- (a - 1)(b - 1)(c - 1) = (-1) \cdot (a - 1)(b - 1)(c - 1)$ $\newline$ Now, distribute the $-1$ to each term inside the first set of parentheses. $\newline$ $(-1) \cdot (a - 1) = (1 - a)$
Apply Distribution: Apply the distributed negative sign to the other terms. $\newline$ Now, we apply the same logic to the other two sets of parentheses. $\newline$ $(-1)\cdot(b-1) = (1-b)$ $\newline$ $(-1)\cdot(c-1) = (1-c)$
Combine Results: Combine the results from Step $1$ and Step $2$ . $\newline$ Now we combine the results of distributing the negative sign to each term. $\newline$ $(1-a)(1-b)(1-c)$
Match with Options: Match the result with the given options. $\newline$ The expression we have obtained is $1-a)(1-b)(1-c)\, which matches option \$B$ .