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Let’s check out your problem:
(
8
3
−
6
)
(
4
3
+
6
)
(8\sqrt{3}-\sqrt{6})(4\sqrt{3}+\sqrt{6})
(
8
3
−
6
)
(
4
3
+
6
)
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Math Problems
Algebra 2
Add, subtract, multiply, and divide polynomials
Full solution
Q.
(
8
3
−
6
)
(
4
3
+
6
)
(8\sqrt{3}-\sqrt{6})(4\sqrt{3}+\sqrt{6})
(
8
3
−
6
)
(
4
3
+
6
)
Identify Expression:
Identify the expression after distributing
(
4
3
+
6
)
(4\sqrt{3} + \sqrt{6})
(
4
3
+
6
)
. Distribute
(
4
3
+
6
)
(4\sqrt{3} + \sqrt{6})
(
4
3
+
6
)
to each term of
(
8
3
−
6
)
(8\sqrt{3} - \sqrt{6})
(
8
3
−
6
)
.
(
8
3
−
6
)
(
4
3
+
6
)
=
8
3
(
4
3
+
6
)
−
6
(
4
3
+
6
)
(8\sqrt{3} - \sqrt{6})(4\sqrt{3} + \sqrt{6}) = 8\sqrt{3}(4\sqrt{3} + \sqrt{6}) - \sqrt{6}(4\sqrt{3} + \sqrt{6})
(
8
3
−
6
)
(
4
3
+
6
)
=
8
3
(
4
3
+
6
)
−
6
(
4
3
+
6
)
Distribute Terms:
Simplify
8
3
(
4
3
+
6
)
8\sqrt{3}(4\sqrt{3} + \sqrt{6})
8
3
(
4
3
+
6
)
.
8
3
(
4
3
+
6
)
8\sqrt{3}(4\sqrt{3} + \sqrt{6})
8
3
(
4
3
+
6
)
=
8
3
(
4
3
)
+
8
3
(
6
)
= 8\sqrt{3}(4\sqrt{3}) + 8\sqrt{3}(\sqrt{6})
=
8
3
(
4
3
)
+
8
3
(
6
)
=
32
×
3
+
8
3
×
6
= 32 \times 3 + 8\sqrt{3 \times 6}
=
32
×
3
+
8
3
×
6
=
96
+
8
18
= 96 + 8\sqrt{18}
=
96
+
8
18
=
96
+
8
×
3
2
= 96 + 8 \times 3\sqrt{2}
=
96
+
8
×
3
2
=
96
+
24
2
= 96 + 24\sqrt{2}
=
96
+
24
2
Simplify First Term:
Simplify
−
6
(
4
3
+
6
)
-\sqrt{6}(4\sqrt{3} + \sqrt{6})
−
6
(
4
3
+
6
)
.
−
6
(
4
3
+
6
)
-\sqrt{6}(4\sqrt{3} + \sqrt{6})
−
6
(
4
3
+
6
)
=
−
6
(
4
3
)
−
6
(
6
)
-\sqrt{6}(4\sqrt{3}) - \sqrt{6}(\sqrt{6})
−
6
(
4
3
)
−
6
(
6
)
=
−
4
18
−
6
-4\sqrt{18} - 6
−
4
18
−
6
=
−
4
×
3
2
−
6
-4 \times 3\sqrt{2} - 6
−
4
×
3
2
−
6
=
−
12
2
−
6
-12\sqrt{2} - 6
−
12
2
−
6
Simplify Second Term:
Combine the results from Step
2
2
2
and Step
3
3
3
.
\newline
96
+
24
2
−
12
2
−
6
96 + 24\sqrt{2} - 12\sqrt{2} - 6
96
+
24
2
−
12
2
−
6
\newline
=
96
−
6
+
24
2
−
12
2
96 - 6 + 24\sqrt{2} - 12\sqrt{2}
96
−
6
+
24
2
−
12
2
\newline
=
90
+
(
24
−
12
)
2
90 + (24 - 12)\sqrt{2}
90
+
(
24
−
12
)
2
\newline
=
90
+
12
2
90 + 12\sqrt{2}
90
+
12
2
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