−553 is a root of f(x)=x2−9,075. Find the other roots of f(x).Write your answer as a list of simplified values separated by commas, if there is more than one value.
Q. −553 is a root of f(x)=x2−9,075. Find the other roots of f(x).Write your answer as a list of simplified values separated by commas, if there is more than one value.
Roots Conjugate Pairs: Since −553 is a root, the other root must also be −553 because the coefficients of the polynomial are real numbers, and non-real roots of polynomials with real coefficients always come in conjugate pairs.
Product of Roots: To find the other root, we can use the fact that the product of the roots of a quadratic equationax2+bx+c=0 is ac. For f(x)=x2−9,075, a=1 and c=−9,075.
Finding Other Root: The product of the roots is −9,075. So, if one root is −553, the other root, let's call it r, must satisfy (−553)×r=−9,075.
Solving for Other Root: Solving for r, we get r=−−5539,075. Simplify this by multiplying the numerator and denominator by 3 to rationalize the denominator.
Simplify Fraction:r=55×3−9,0753. Now, simplify the fraction.
Final Result:r=165−9,0753. Divide both numerator and denominator by 165.
Final Result:r=165−9,0753. Divide both numerator and denominator by 165.r=−553. So, the other root is also −553.