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${:[4x^(2)+x-29=y],[x-4=y]:} If (x,y) is a solution to the system of equations shown and x > 0, what is the value of x ?$

$4x^2 + x - 29 = y$ $\newline$ $x - 4 = y$ $\newline$ If $(x,y)$ is a solution to the system of equations shown and x > 0, what is the value of $x$ ?

Full solution

4x^2 + x - 29 = y

\newline

x - 4 = y

\newline

(x,y)

is a solution to the system of equations shown and

x > 0

, what is the value of

x

Substitute $y$ in first equation: First, let's use the second equation $x - 4 = y$ to substitute $y$ in the first equation.
Solve for x: Substitute $y$ with $x - 4$ in the first equation: $4x^2 + x - 29 = x - 4$ .
Subtract $x$ from both sides: Now, let's solve for $x$ : $4x^2 + x - 29 = x - 4$ .
Subtract $x$ from both sides: Now, let's solve for $x$ : $4x^2 + x - 29 = x - 4$ .Subtract $x$ from both sides to get: $4x^2 - 29 = -4$ .