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${:[=4(5e^(-1//2))^(2)ln(e^(-1//2))],[=4(5e^(-1//2))^(2)(◻)/(2)=◻e^(◻)]:}$

$\begin{array}{l}=4\left(5 e^{-1 / 2}\right)^{2} \ln \left(e^{-1 / 2}\right) \\ =4\left(5 e^{-1 / 2}\right)^{2} \frac{\square}{2}=\square e^{\square}\end{array}$

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Find the limit at a vertical asymptote of a rational function II

Full solution

Q.

\begin{array}{l}=4\left(5 e^{-1 / 2}\right)^{2} \ln \left(e^{-1 / 2}\right) \\ =4\left(5 e^{-1 / 2}\right)^{2} \frac{\square}{2}=\square e^{\square}\end{array}

Given Information: We know: Total amount of electrical tape needed: $8,000$ cm Amount of tape in each roll: $2,000$ cm Which expression represents the number of rolls needed? We should use division to find the number of rolls needed. Total amount of tape needed $\div$ Amount of tape in each roll $8,000 \div 2,000$
Expression for Rolls Needed: Evaluate $8,000 \div 2,000$ to find the number of rolls of tape needed. $8,000 \div 2,000 = 4$ Number of rolls needed: $4$ rolls

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