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(3s+1)(s-4)=-5(s-1)

(3s+1)(s4)=5(s1) (3 s+1)(s-4)=-5(s-1)

Full solution

Q. (3s+1)(s4)=5(s1) (3 s+1)(s-4)=-5(s-1)
  1. Expand Left Side: Expand the left side of the equation (3s+1)(s4)(3s+1)(s-4). We distribute each term in the first parenthesis by each term in the second parenthesis. (3s+1)(s4)=3s(s)+3s(4)+1(s)+1(4)(3s+1)(s-4) = 3s(s) + 3s(-4) + 1(s) + 1(-4)
  2. Simplify Expanded Expression: Simplify the expanded expression.\newline3s(s)+3s(4)+1(s)+1(4)=3s212s+s43s(s) + 3s(-4) + 1(s) + 1(-4) = 3s^2 - 12s + s - 4\newlineCombine like terms.\newline3s212s+s4=3s211s43s^2 - 12s + s - 4 = 3s^2 - 11s - 4
  3. Combine Like Terms: Expand the right side of the equation 5(s1)-5(s-1).\newlineWe distribute 5-5 to each term inside the parenthesis.\newline5(s1)=5s+5-5(s-1) = -5s + 5
  4. Expand Right Side: Set the expanded left side equal to the expanded right side.\newline3s211s4=5s+53s^2 - 11s - 4 = -5s + 5
  5. Set Equation Equal: Move all terms to one side to set the equation to zero.\newlineAdd 5s5s to both sides and subtract 55 from both sides.\newline3s211s+5s45=03s^2 - 11s + 5s - 4 - 5 = 0\newlineCombine like terms.\newline3s26s9=03s^2 - 6s - 9 = 0

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