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Let’s check out your problem:
(
3
5
a
+
4
7
)
2
\left(\frac{3}{5}a+\frac{4}{7}\right)^2
(
5
3
a
+
7
4
)
2
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Math Problems
Algebra 1
Add and subtract polynomials
Full solution
Q.
(
3
5
a
+
4
7
)
2
\left(\frac{3}{5}a+\frac{4}{7}\right)^2
(
5
3
a
+
7
4
)
2
Write Expression:
First, write down the expression to be squared.
\newline
(
3
5
a
+
4
7
)
2
(\frac{3}{5}a + \frac{4}{7})^2
(
5
3
a
+
7
4
)
2
Apply Formula:
Now, apply the formula
(
a
+
b
)
2
=
a
2
+
2
a
b
+
b
2
(a + b)^2 = a^2 + 2ab + b^2
(
a
+
b
)
2
=
a
2
+
2
ab
+
b
2
to the expression.
(
3
5
a
)
2
+
2
⋅
(
3
5
a
)
⋅
(
4
7
)
+
(
4
7
)
2
(\frac{3}{5}a)^2 + 2\cdot(\frac{3}{5}a)\cdot(\frac{4}{7}) + (\frac{4}{7})^2
(
5
3
a
)
2
+
2
⋅
(
5
3
a
)
⋅
(
7
4
)
+
(
7
4
)
2
Calculate Terms:
Calculate each term separately.
\newline
(
3
5
a
)
2
=
(
3
2
5
2
)
a
2
=
9
25
a
2
(\frac{3}{5}a)^2 = (\frac{3^2}{5^2})a^2 = \frac{9}{25}a^2
(
5
3
a
)
2
=
(
5
2
3
2
)
a
2
=
25
9
a
2
\newline
2
⋅
(
3
5
a
)
⋅
(
4
7
)
=
2
⋅
(
3
⋅
4
5
⋅
7
)
a
=
24
35
a
2\cdot(\frac{3}{5}a)\cdot(\frac{4}{7}) = 2\cdot(\frac{3\cdot4}{5\cdot7})a = \frac{24}{35}a
2
⋅
(
5
3
a
)
⋅
(
7
4
)
=
2
⋅
(
5
⋅
7
3
⋅
4
)
a
=
35
24
a
\newline
(
4
7
)
2
=
16
49
(\frac{4}{7})^2 = \frac{16}{49}
(
7
4
)
2
=
49
16
Combine Final Answer:
Combine all the terms to get the final answer.
9
25
a
2
+
24
35
a
+
16
49
\frac{9}{25}a^2 + \frac{24}{35}a + \frac{16}{49}
25
9
a
2
+
35
24
a
+
49
16
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(
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−
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\newline
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(
r
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)
(
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\newline
(
x
+
7
)
(
x
+
4
)
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(
x
+
7
)
(
x
+
4
)
\newline
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\newline
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