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-3*(10 i+6)=
Your answer should be a complex number in the form
a+bi where
a and
b are real numbers.

$-3 \cdot(10 i+6)=$ $\newline$ Your answer should be a complex number in the form $a+b i$ where $a$ and $b$ are real numbers.

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Write equations of cosine functions using properties

Full solution

Q.

-3 \cdot(10 i+6)=

\newline

Your answer should be a complex number in the form

a+b i

where

a

and

b

are real numbers.

Distribute real number $-3$ : Distribute the real number $-3$ to both the real and imaginary parts of the complex number $10i + 6$ . $\newline$ Calculation: $-3 \times (10i + 6) = -3 \times 10i + -3 \times 6$
Multiply $-3$ with imaginary and real parts: Multiply the real number $-3$ with the imaginary part $10i$ and the real part $6$ separately. $\newline$ Calculation: $-3 \times 10i = -30i$ and $-3 \times 6 = -18$
Combine results to form final complex number: Combine the results from Step $2$ to form the final complex number. $\newline$ Calculation: The complex number is $-18 - 30i$ .

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