(2x-(7-5x))/(9x-(3+4x))=(7)/(6)

Simplify Numerator and Denominator: Simplify the numerator and the denominator. Numerator: 2x - (7 - 5x) = 2x - 7 + 5x = 7x - 7 Denominator: 9x - (3 + 4x) = 9x - 3 - 4x = 5x - 3 Equation becomes: (7x - 7) / (5x - 3) = 7 / 6Cross-Multiply to Eliminate Fractions: Cross-multiply to eliminate the fractions. (7x - 7) * 6 = 7 * (5x - 3) 42x - 42 = 35x - 21Solve for x: Solve for x. 42x - 35x = -21 + 42 7x = 21 x = 21 / 7 x = 3

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Find $x$ $\newline$ $\frac{2 x-(7-5 x)}{9 x-(3+4 x)}=\frac{7}{6}$

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Algebra 2

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Q. Find

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\newline

\frac{2 x-(7-5 x)}{9 x-(3+4 x)}=\frac{7}{6}

Simplify Numerator and Denominator: Simplify the numerator and the denominator. $\newline$ Numerator: $2x - (7 - 5x) = 2x - 7 + 5x = 7x - 7$ $\newline$ Denominator: $9x - (3 + 4x) = 9x - 3 - 4x = 5x - 3$ $\newline$ Equation becomes: $(7x - 7) / (5x - 3) = 7 / 6$
Cross-Multiply to Eliminate Fractions: Cross-multiply to eliminate the fractions. $\newline$ $(7x - 7) \times 6 = 7 \times (5x - 3)$ $\newline$ $42x - 42 = 35x - 21$
Solve for x: Solve for x. $\newline$ $42x - 35x = -21 + 42$ $\newline$ $7x = 21$ $\newline$ $x = \frac{21}{7}$ $\newline$ $x = 3$