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(2x^(3)+4x^(2)+3x+1)÷(2x+1)

(2x3+4x2+3x+1)÷(2x+1) \left(2 x^{3}+4 x^{2}+3 x+1\right) \div(2 x+1)

Full solution

Q. (2x3+4x2+3x+1)÷(2x+1) \left(2 x^{3}+4 x^{2}+3 x+1\right) \div(2 x+1)
  1. Use polynomial long division: To divide the polynomial (2x3+4x2+3x+1)(2x^3 + 4x^2 + 3x + 1) by the binomial (2x+1)(2x + 1), we will use polynomial long division.
  2. Divide leading terms: First, we divide the leading term of the numerator, 2x32x^3, by the leading term of the denominator, 2x2x. This gives us x2x^2. We then multiply the entire denominator (2x+1)(2x + 1) by x2x^2 and subtract the result from the original polynomial.
  3. Subtract and multiply: Multiplying (2x+1)(2x + 1) by x2x^2 gives us 2x3+x22x^3 + x^2. We write this below the original polynomial and subtract.(2x3+4x2)(2x3+x2)=3x2(2x^3 + 4x^2) - (2x^3 + x^2) = 3x^2.
  4. Bring down next term: Bring down the next term of the original polynomial to get 3x2+3x3x^2 + 3x. Now, divide the leading term of this result, 3x23x^2, by the leading term of the denominator, 2x2x, to get (32)x(\frac{3}{2})x.
  5. Divide leading terms again: Multiply the entire denominator (2x+1)(2x + 1) by (32)x(\frac{3}{2})x and subtract the result from (3x2+3x)(3x^2 + 3x). Multiplying gives us (3x2+(32)x)(3x^2 + (\frac{3}{2})x), which we subtract from (3x2+3x)(3x^2 + 3x) to get (3x(32)x)(3x - (\frac{3}{2})x).
  6. Subtract and multiply: Simplifying (3x(32)x)(3x - (\frac{3}{2})x) gives us (32)x(\frac{3}{2})x. Bring down the next term of the original polynomial to get (32)x+1(\frac{3}{2})x + 1. Now, divide the leading term of this result, (32)x(\frac{3}{2})x, by the leading term of the denominator, 2x2x, to get 34\frac{3}{4}.
  7. Bring down next term again: Multiply the entire denominator 2x+12x + 1 by 34\frac{3}{4} and subtract the result from (32)x+1\left(\frac{3}{2}\right)x + 1. Multiplying gives us (32)x+34\left(\frac{3}{2}\right)x + \frac{3}{4}, which we subtract from (32)x+1\left(\frac{3}{2}\right)x + 1 to get the remainder.
  8. Divide leading terms once more: Simplifying 1341 - \frac{3}{4} gives us 14\frac{1}{4}. So, the remainder is 14\frac{1}{4}, and the quotient we have obtained is x2+32x+34x^2 + \frac{3}{2}x + \frac{3}{4}.
  9. Subtract and find remainder: The final answer is the quotient plus the remainder over the original divisor: x2+(32)x+34+14(12x+1)x^2 + \left(\frac{3}{2}\right)x + \frac{3}{4} + \frac{1}{4}\left(\frac{1}{2x + 1}\right).

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