Use polynomial long division: To divide the polynomial (2x3+4x2+3x+1) by the binomial (2x+1), we will use polynomial long division.
Divide leading terms: First, we divide the leading term of the numerator, 2x3, by the leading term of the denominator, 2x. This gives us x2. We then multiply the entire denominator (2x+1) by x2 and subtract the result from the original polynomial.
Subtract and multiply: Multiplying (2x+1) by x2 gives us 2x3+x2. We write this below the original polynomial and subtract.(2x3+4x2)−(2x3+x2)=3x2.
Bring down next term: Bring down the next term of the original polynomial to get 3x2+3x. Now, divide the leading term of this result, 3x2, by the leading term of the denominator, 2x, to get (23)x.
Divide leading terms again: Multiply the entire denominator (2x+1) by (23)x and subtract the result from (3x2+3x). Multiplying gives us (3x2+(23)x), which we subtract from (3x2+3x) to get (3x−(23)x).
Subtract and multiply: Simplifying (3x−(23)x) gives us (23)x. Bring down the next term of the original polynomial to get (23)x+1. Now, divide the leading term of this result, (23)x, by the leading term of the denominator, 2x, to get 43.
Bring down next term again: Multiply the entire denominator 2x+1 by 43 and subtract the result from (23)x+1. Multiplying gives us (23)x+43, which we subtract from (23)x+1 to get the remainder.
Divide leading terms once more: Simplifying 1−43 gives us 41. So, the remainder is 41, and the quotient we have obtained is x2+23x+43.
Subtract and find remainder: The final answer is the quotient plus the remainder over the original divisor: x2+(23)x+43+41(2x+11).
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