(2x-1)(x-5)(x+2)=0 What is a positive root of the given equation? ◻

Given Equation Roots: We are given the equation (2x-1)(x-5)(x+2)=0. To find the roots of the equation, we need to set each factor equal to zero and solve for x.Factor 1: First, let's set the first factor equal to zero: 2x - 1 = 0. Solving for x gives us x = 1/2.Factor 2: Next, we set the second factor equal to zero: x - 5 = 0. Solving for x gives us x = 5.Factor 3: Finally, we set the third factor equal to zero: x + 2 = 0. Solving for x gives us x = -2.Positive Roots: Now we have three roots: x = 1/2, x = 5, and x = -2. The question asks for the positive root.Final Answer: Looking at the roots we found, the positive roots are x = 1/2 and x = 5. Since we are asked for a single positive root, we will provide both as the answer.

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(2x-1)(x-5)(x+2)=0
What is a positive root of the given equation?

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$(2 x-1)(x-5)(x+2)=0$ $\newline$ What is a positive root of the given equation? $\newline$ $\square$

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(2 x-1)(x-5)(x+2)=0

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What is a positive root of the given equation?

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Given Equation Roots: We are given the equation 2x-1)(x-5)(x+2)=0\. To find the roots of the equation, we need to set each factor equal to zero and solve for \$x.
Factor $1$ : First, let's set the first factor equal to zero: $2x - 1 = 0$ . Solving for $x$ gives us $x = \frac{1}{2}$ .
Factor $2$ : Next, we set the second factor equal to zero: $x - 5 = 0$ . $\newline$ Solving for $x$ gives us $x = 5$ .
Factor $3$ : Finally, we set the third factor equal to zero: $x + 2 = 0$ . Solving for $x$ gives us $x = -2$ .
Positive Roots: Now we have three roots: $x = \frac{1}{2}$ , $x = 5$ , and $x = -2$ . The question asks for the positive root.
Final Answer: Looking at the roots we found, the positive roots are $x = \frac{1}{2}$ and $x = 5$ . Since we are asked for a single positive root, we will provide both as the answer.