(23^(0)+24^(0)+25^(0))^(-2)÷9

Evaluate Exponents with Base 0: Evaluate the exponents with base 0. According to the exponent rule, any non-zero number raised to the power of 0 is 1. So, 23^(0) = 1, 24^(0) = 1, and 25^(0) = 1.Add Results from Step 1: Add the results from Step 1. 1 + 1 + 1 = 3Raise Sum to Power of -2: Raise the sum to the power of -2. (3)^(-2) means 1 divided by (3)^2.Calculate (3)^2: Calculate (3)^2. (3)^2 = 3 * 3 = 9Calculate 1 divided by (3)^2: Calculate 1 divided by (3)^2. 1 / 9 = 1/9Divide Result by 9: Divide the result from Step 5 by 9. (1/9) ÷ 9 = (1/9) * (1/9) = 1/81

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$\left(23^{0}+24^{0}+25^{0}\right)^{-2} \div 9$

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Algebra 2

Divide polynomials using long division

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\left(23^{0}+24^{0}+25^{0}\right)^{-2} \div 9

Evaluate Exponents with Base $0$ : Evaluate the exponents with base $0$ . $\newline$ According to the exponent rule, any non-zero number raised to the power of $0$ is $1$ . $\newline$ So, $23^{0} = 1$ , $24^{0} = 1$ , and $25^{0} = 1$ .
Add Results from Step $1$ : Add the results from Step $1$ . $\newline$ $1 + 1 + 1 = 3$
Raise Sum to Power of $-2$ : Raise the sum to the power of $-2$ . $(3)^{-2}$ means $1$ divided by $(3)^2$ .
Calculate $(3)^2$ : Calculate $(3)^2$ . $(3)^2 = 3 \times 3 = 9$
Calculate $1$ divided by $(3)^2$ : Calculate $1$ divided by $(3)^2$ . $\frac{1}{9} = \frac{1}{9}$
Divide Result by $9$ : Divide the result from Step $5$ by $9$ . $\newline$ $(1/9) \div 9 = (1/9) \times (1/9) = 1/81$