Given Matrix Equation: We are given the matrix equation \begin{bmatrix}-22\27\end{bmatrix} = \begin{bmatrix}2 & 4\-3 & -7\end{bmatrix}\mathbf{Y} + \begin{bmatrix}-8\7\end{bmatrix}, and we need to solve for the matrix Y. Let's denote the matrix \begin{bmatrix}2 & 4\-3 & -7\end{bmatrix} as A and the matrix Y as Y. The equation can be rewritten as: \mathbf{A} \cdot \mathbf{Y} = \begin{bmatrix}-22\27\end{bmatrix} - \begin{bmatrix}-8\7\end{bmatrix}
Subtracting Matrices: First, we need to subtract the matrix [[−8],[7]] from the matrix [[−22],[27]] to isolate A∗Y on one side of the equation.[[-22],[27]] - [[-8],[7]] = [[-22 - (-8)],[27 - 7]]\(\newline= [[-22 + 8],[20]]= [[-14],[20]]\)
Finding Inverse of Matrix: Now we have the equation A∗Y=[−1420]. We need to find the inverse of matrix A, which is [2amp;4−3amp;−7], in order to solve for Y.
Calculating Determinant: The inverse of a 2×2 matrix [aamp;bcamp;d] is given by (ad−bc1)×[damp;−b−camp;a]. Let's calculate the determinant (ad−bc) for matrix A.Determinant = (2×−7)−(4×−3)= −14+12= −2
Calculating Inverse: Since the determinant is not zero, matrix A is invertible. Now we can calculate the inverse of A.A−1=(Determinant1)∗[−7amp;−43amp;2]=(−21)∗[−7amp;−43amp;2]=[27amp;24−23amp;−22]=[3.5amp;2−1.5amp;−1]
Multiplying Matrices: Now that we have A−1, we can multiply it by the matrix \begin{bmatrix}-14\20\end{bmatrix} to solve for Y.Y = A^{-1} \times \begin{bmatrix}-14\20\end{bmatrix} = \begin{bmatrix}3.5 & 2\-1.5 & -1\end{bmatrix} \times \begin{bmatrix}-14\20\end{bmatrix}