(2) ((x-1))/(6)=((x+5))/(5)

Set up equation: Set up the equation. We have the equation (x - 1)/6 = (x + 5)/5. We need to find the value of x that satisfies this equation.Cross-multiply: Cross-multiply to eliminate the fractions. Cross-multiplying gives us 5(x - 1) = 6(x + 5).Distribute numbers: Distribute the numbers on both sides. 5(x - 1) = 5x - 5 6(x + 5) = 6x + 30 Now we have the equation 5x - 5 = 6x + 30.Move x terms: Move the x terms to one side and the constant terms to the other side. Subtract 5x from both sides to get -5 = x + 30.Isolate x: Isolate x. Subtract 30 from both sides to get x = -5 - 30.Simplify equation: Simplify the equation to find the value of x. x = -35

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( $2$ ) $\frac{(x-1)}{6}=\frac{(x+5)}{5}$

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Algebra 2

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\frac{(x-1)}{6}=\frac{(x+5)}{5}

Set up equation: Set up the equation. $\newline$ We have the equation $(x - 1)/6 = (x + 5)/5$ . We need to find the value of $x$ that satisfies this equation.
Cross-multiply: Cross-multiply to eliminate the fractions. $\newline$ Cross-multiplying gives us $5(x - 1) = 6(x + 5)$ .
Distribute numbers: Distribute the numbers on both sides. $\newline$ $5(x - 1) = 5x - 5$ $\newline$ $6(x + 5) = 6x + 30$ $\newline$ Now we have the equation $5x - 5 = 6x + 30$ .
Move $x$ terms: Move the $x$ terms to one side and the constant terms to the other side. $\newline$ Subtract $5x$ from both sides to get $-5 = x + 30$ .
Isolate $x$ : Isolate $x$ . $\newline$ Subtract $30$ from both sides to get $x = -5 - 30$ .
Simplify equation: Simplify the equation to find the value of $x$ . $x = -35$