Q. 12t=4v−3−6t=4v+6If (t,v) is the solution to the system of equations, what is the value of t−v ?□
Write Equations: First, let's write down the system of equations we need to solve:1) 12t=4v−32) −6t=4v+6We need to find the values of t and v that satisfy both equations simultaneously.
Elimination Method: To solve the system, we can use the method of elimination or substitution. Let's use elimination by adding the two equations together to eliminate v. Before we do that, we need to make the coefficients of v the same in both equations. We can multiply the second equation by −1 to get the coefficients of v to be opposites.Multiplying the second equation by −1 gives us:−1×(−6t)=−1×(4v+6)6t=−4v−6Now we have:1) 12t=4v−33) 6t=−4v−6
Add Equations: Next, we add equations 1) and 3) together to eliminate v:(12t)+(6t)=(4v−3)+(−4v−6)This simplifies to:18t=−9
Solve for t: Now we can solve for t by dividing both sides of the equation by 18:1818t=18−9t=−21
Substitute for v: With the value of t found, we can substitute it back into one of the original equations to find v. Let's use equation 1):12t=4v−312(−21)=4v−3−6=4v−3
Add 3 to Solve for v: Now, we add 3 to both sides of the equation to solve for v:−6+3=4v−3+3−3=4v
Divide by 4 for v: Finally, we divide both sides by 4 to find the value of v:−43=44vv=−43
Find t−v: Now that we have both t and v, we can find the value of t−v: t−v=(−21)−(−43)To subtract these fractions, we need a common denominator, which is 4:t−v=(−42)−(−43)t−v=(−42)+(43)t−v=41