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{:[12 t=4v-3],[-6t=4v+6]:}
If 
(t,v) is the solution to the system of equations, what is the value of 
t-v ?

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12t=4v36t=4v+6 \begin{array}{r} 12 t=4 v-3 \\ -6 t=4 v+6 \end{array} \newlineIf (t,v) (t, v) is the solution to the system of equations, what is the value of tv t-v ?\newline \square

Full solution

Q. 12t=4v36t=4v+6 \begin{array}{r} 12 t=4 v-3 \\ -6 t=4 v+6 \end{array} \newlineIf (t,v) (t, v) is the solution to the system of equations, what is the value of tv t-v ?\newline \square
  1. Write Equations: First, let's write down the system of equations we need to solve:\newline11) 12t=4v312t = 4v - 3\newline22) 6t=4v+6-6t = 4v + 6\newlineWe need to find the values of tt and vv that satisfy both equations simultaneously.
  2. Elimination Method: To solve the system, we can use the method of elimination or substitution. Let's use elimination by adding the two equations together to eliminate vv. Before we do that, we need to make the coefficients of vv the same in both equations. We can multiply the second equation by 1-1 to get the coefficients of vv to be opposites.\newlineMultiplying the second equation by 1-1 gives us:\newline1×(6t)=1×(4v+6)-1 \times (-6t) = -1 \times (4v + 6)\newline6t=4v66t = -4v - 6\newlineNow we have:\newline11) 12t=4v312t = 4v - 3\newline33) 6t=4v66t = -4v - 6
  3. Add Equations: Next, we add equations 11) and 33) together to eliminate vv:(12t)+(6t)=(4v3)+(4v6)(12t) + (6t) = (4v - 3) + (-4v - 6)This simplifies to:18t=918t = -9
  4. Solve for t: Now we can solve for t by dividing both sides of the equation by 1818:\newline18t18=918\frac{18t}{18} = \frac{-9}{18}\newlinet=12t = -\frac{1}{2}
  5. Substitute for v: With the value of tt found, we can substitute it back into one of the original equations to find vv. Let's use equation 11):12t=4v312t = 4v - 312(12)=4v312(-\frac{1}{2}) = 4v - 36=4v3-6 = 4v - 3
  6. Add 33 to Solve for v: Now, we add 33 to both sides of the equation to solve for v:\newline6+3=4v3+3-6 + 3 = 4v - 3 + 3\newline3=4v-3 = 4v
  7. Divide by 44 for v: Finally, we divide both sides by 44 to find the value of v:\newline34=4v4-\frac{3}{4} = \frac{4v}{4}\newlinev=34v = -\frac{3}{4}
  8. Find tvt - v: Now that we have both tt and vv, we can find the value of tvt - v: \newlinetv=(12)(34)t - v = \left(-\frac{1}{2}\right) - \left(-\frac{3}{4}\right)\newlineTo subtract these fractions, we need a common denominator, which is 44:\newlinetv=(24)(34)t - v = \left(-\frac{2}{4}\right) - \left(-\frac{3}{4}\right)\newlinetv=(24)+(34)t - v = \left(-\frac{2}{4}\right) + \left(\frac{3}{4}\right)\newlinetv=14t - v = \frac{1}{4}