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(10) 
2x^(2)+x-45

(1010) 2x2+x45 2 x^{2}+x-45

Full solution

Q. (1010) 2x2+x45 2 x^{2}+x-45
  1. Identify quadratic expression: Identify the quadratic expression to be factored.\newlineThe given expression is 2x2+x452x^2 + x - 45.
  2. Determine factors: Determine the factors of the quadratic coefficient 22 and the constant term 45-45. The factors of 22 are 11 and 22. The factors of 45-45 are ±1\pm1, ±3\pm3, ±5\pm5, ±9\pm9, 45-4500, 45-4511. We need to find a pair of factors that multiply to 45-4522 (45-4533) and add up to 11 (the coefficient of 45-4555).
  3. Find correct pair: Find the correct pair of factors.\newlineAfter checking possible combinations, we find that 1010 and 9-9 are the factors that meet the criteria.\newline10×9=9010 \times -9 = -90 and 10+(9)=110 + (-9) = 1.
  4. Write middle term: Write the middle term xx as the sum of two terms using the factors 1010 and 9-9.2x2+x452x^2 + x - 45 becomes 2x2+10x9x452x^2 + 10x - 9x - 45.
  5. Group terms: Group the terms to factor by grouping.\newline(2x2+10x)+(9x45)(2x^2 + 10x) + (-9x - 45)
  6. Factor out common factor: Factor out the greatest common factor from each group. 2x(x+5)9(x+5)2x(x + 5) - 9(x + 5)
  7. Factor out binomial factor: Factor out the common binomial factor (x+5)(x + 5).\newline(2x9)(x+5)(2x - 9)(x + 5)

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