For the function, f(x)=x^(2)-3x+9 Find when f(x)=7. x=◻

Set Equation Equal: To find the values of x for which f(x) = 7, we need to solve the equation f(x) = 7 using the given function f(x) = x^2 - 3x + 9. Set f(x) equal to 7 and solve for x: x^2 - 3x + 9 = 7Subtract Constant Term: Subtract 7 from both sides of the equation to move the constant term to the left side: x^2 - 3x + 9 - 7 = 0 x^2 - 3x + 2 = 0Factor Quadratic Equation: Now, we need to factor the quadratic equation or use the quadratic formula to find the values of x. Let's try to factor it first: (x - 1)(x - 2) = 0Solve for x: Set each factor equal to zero and solve for x: x - 1 = 0 or x - 2 = 0 x = 1 or x = 2

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For the function, f(x)=x^(2)-3x+9
Find when f(x)=7.
x=◻

For the function, $f(x)=x^{2}-3 x+9$ $\newline$ Find when $f(x)=7$ . $\newline$ $x= \square$

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Algebra 2

Composition of linear and quadratic functions: find an equation

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Q. For the function,

f(x)=x^{2}-3 x+9

\newline

Find when

f(x)=7

\newline

x= \square

Set Equation Equal: To find the values of $x$ for which $f(x) = 7$ , we need to solve the equation $f(x) = 7$ using the given function $f(x) = x^2 - 3x + 9$ . $\newline$ Set $f(x)$ equal to $7$ and solve for $x$ : $\newline$ $x^2 - 3x + 9 = 7$
Subtract Constant Term: Subtract $7$ from both sides of the equation to move the constant term to the left side: $\newline$ $x^2 - 3x + 9 - 7 = 0$ $\newline$ $x^2 - 3x + 2 = 0$
Factor Quadratic Equation: Now, we need to factor the quadratic equation or use the quadratic formula to find the values of $x$ . Let's try to factor it first: $\newline$ $(x - 1)(x - 2) = 0$
Solve for x: Set each factor equal to zero and solve for x: $\newline$ $x - 1 = 0$ or $x - 2 = 0$ $\newline$ $x = 1$ or $x = 2$