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/_1 and 
/_2 are vertical angles. If 
m/_1=(8x-28)^(@) and 
m/_2=(4x+4)^(@), then find the measure of 
/_2.
Answer:

1 \angle 1 and 2 \angle 2 are vertical angles. If m1=(8x28) \mathrm{m} \angle 1=(8 x-28)^{\circ} and m2=(4x+4) \mathrm{m} \angle 2=(4 x+4)^{\circ} , then find the measure of 2 \angle 2 .\newlineAnswer:

Full solution

Q. 1 \angle 1 and 2 \angle 2 are vertical angles. If m1=(8x28) \mathrm{m} \angle 1=(8 x-28)^{\circ} and m2=(4x+4) \mathrm{m} \angle 2=(4 x+4)^{\circ} , then find the measure of 2 \angle 2 .\newlineAnswer:
  1. Set Equal Expressions: Vertical angles are congruent, which means they have equal measures. Therefore, we can set the expressions for m/angle 1m/\text{angle } 1 and m/angle 2m/\text{angle } 2 equal to each other to find the value of xx.\newlineEquation: (8x28)=(4x+4)(8x - 28) = (4x + 4)
  2. Subtract x Terms: Now, we will solve for xx by first subtracting 4x4x from both sides of the equation to get the xx terms on one side.(8x28)4x=(4x+4)4x(8x - 28) - 4x = (4x + 4) - 4x4x28=44x - 28 = 4
  3. Add 2828: Next, we will add 2828 to both sides of the equation to isolate the xx term.\newline4x28+28=4+284x - 28 + 28 = 4 + 28\newline4x=324x = 32
  4. Divide by 44: Now, we will divide both sides of the equation by 44 to solve for xx.4x4=324\frac{4x}{4} = \frac{32}{4}x=8x = 8
  5. Substitute x Value: With the value of xx found, we can now substitute it back into the expression for m/angle 2m/\text{angle } 2 to find its measure.\newlinem/angle 2=(4x+4)m/\text{angle } 2 = (4x + 4)\newlinem/angle 2=(4×8)+4m/\text{angle } 2 = (4 \times 8) + 4\newlinem/angle 2=32+4m/\text{angle } 2 = 32 + 4\newlinem/angle 2=36m/\text{angle } 2 = 36 degrees

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