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/_1 and 
/_2 are vertical angles. If 
m/_1=(8x-10)^(@) and 
m/_2=(6x+26)^(@), then find the value of 
x.
Answer:

1 \angle 1 and 2 \angle 2 are vertical angles. If m1=(8x10) \mathrm{m} \angle 1=(8 x-10)^{\circ} and m2=(6x+26) \mathrm{m} \angle 2=(6 x+26)^{\circ} , then find the value of x x .\newlineAnswer:

Full solution

Q. 1 \angle 1 and 2 \angle 2 are vertical angles. If m1=(8x10) \mathrm{m} \angle 1=(8 x-10)^{\circ} and m2=(6x+26) \mathrm{m} \angle 2=(6 x+26)^{\circ} , then find the value of x x .\newlineAnswer:
  1. Set Equal Expressions: Vertical angles are congruent, which means they have equal measures. Therefore, we can set the expressions for m/1m/\angle_1 and m/2m/\angle_2 equal to each other to find the value of xx.(8x10)=(6x+26)(8x - 10) = (6x + 26)
  2. Combine Like Terms: To solve for xx, we need to get all the xx terms on one side and the constant terms on the other side. We can do this by subtracting 6x6x from both sides and adding 1010 to both sides.\newline8x106x=6x+266x8x - 10 - 6x = 6x + 26 - 6x\newline8x6x10+10=26+108x - 6x - 10 + 10 = 26 + 10
  3. Simplify Equation: Simplify the equation by combining like terms. 2x=362x = 36
  4. Divide by 22: To find the value of xx, divide both sides of the equation by 22.x=362x = \frac{36}{2}
  5. Calculate Value: Calculate the value of xx.x=18x = 18

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