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/_1 and 
/_2 are vertical angles. If 
m/_1=(7x-14)^(@) and 
m/_2=(4x+25)^(@), then find the value of 
x.
Answer:

1 \angle 1 and 2 \angle 2 are vertical angles. If m1=(7x14) \mathrm{m} \angle 1=(7 x-14)^{\circ} and m2=(4x+25) \mathrm{m} \angle 2=(4 x+25)^{\circ} , then find the value of x x .\newlineAnswer:

Full solution

Q. 1 \angle 1 and 2 \angle 2 are vertical angles. If m1=(7x14) \mathrm{m} \angle 1=(7 x-14)^{\circ} and m2=(4x+25) \mathrm{m} \angle 2=(4 x+25)^{\circ} , then find the value of x x .\newlineAnswer:
  1. Set Angle Expressions Equal: Vertical angles are congruent, which means they have equal measures. Therefore, we can set the expressions for m/1m/\angle_1 and m/2m/\angle_2 equal to each other to find the value of xx.(7x14)=(4x+25)(7x - 14) = (4x + 25)
  2. Subtract 4x4x: Subtract 4x4x from both sides to start isolating the variable xx on one side of the equation.\newline7x144x=4x+254x7x - 14 - 4x = 4x + 25 - 4x\newlineThis simplifies to:\newline3x14=253x - 14 = 25
  3. Add 1414: Add 1414 to both sides to further isolate xx.\newline3x14+14=25+143x - 14 + 14 = 25 + 14\newlineThis simplifies to:\newline3x=393x = 39
  4. Divide by 33: Divide both sides by 33 to solve for xx.3x3=393\frac{3x}{3} = \frac{39}{3}This simplifies to:x=13x = 13

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