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/_1 and /_2 are supplementary angles. If m/_1=(4x-16)^(@) and m/_2=(x+1)^(@), then find the measure of /_2.

1 \angle 1 and 2 \angle 2 are supplementary angles. If m1=(4x16) \mathrm{m} \angle 1=(4 x-16)^{\circ} and m2=(x+1) \mathrm{m} \angle 2=(x+1)^{\circ} , then find the measure of 2 \angle 2 .

Full solution

Q. 1 \angle 1 and 2 \angle 2 are supplementary angles. If m1=(4x16) \mathrm{m} \angle 1=(4 x-16)^{\circ} and m2=(x+1) \mathrm{m} \angle 2=(x+1)^{\circ} , then find the measure of 2 \angle 2 .
  1. Set up equation: Supplementary angles add up to 180180 degrees. We can set up an equation with the given expressions for m/angle 1m/\text{angle } 1 and m/angle 2m/\text{angle } 2 to find the value of xx.\newlineCalculation: (4x16)+(x+1)=180(4x - 16) + (x + 1) = 180
  2. Simplify equation: Combine like terms to simplify the equation.\newlineCalculation: 4x+x16+1=1804x + x - 16 + 1 = 180\newline5x15=1805x - 15 = 180
  3. Isolate xx: Add 1515 to both sides of the equation to isolate the term with xx.\newlineCalculation: 5x15+15=180+155x - 15 + 15 = 180 + 15\newline5x=1955x = 195
  4. Solve for x: Divide both sides of the equation by 55 to solve for x.\newlineCalculation: 5x5=1955\frac{5x}{5} = \frac{195}{5}\newlinex=39x = 39
  5. Find angle 22: Now that we have the value of xx, we can find the measure of angle 22 by substituting xx into the expression for m/angle 2m/\text{angle } 2.\newlineCalculation: m/angle 2=(x+1)m/\text{angle } 2 = (x + 1) degrees\newlinem/angle 2=(39+1)m/\text{angle } 2 = (39 + 1) degrees\newlinem/angle 2=40m/\text{angle } 2 = 40 degrees

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