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/_1 and 
/_2 are supplementary angles. If 
m/_1=(5x-6)^(@) and 
m/_2=(5x-4)^(@), then find the measure of 
/_1.
Answer:

1 \angle 1 and 2 \angle 2 are supplementary angles. If m1=(5x6) \mathrm{m} \angle 1=(5 x-6)^{\circ} and m2=(5x4) \mathrm{m} \angle 2=(5 x-4)^{\circ} , then find the measure of 1 \angle 1 .\newlineAnswer:

Full solution

Q. 1 \angle 1 and 2 \angle 2 are supplementary angles. If m1=(5x6) \mathrm{m} \angle 1=(5 x-6)^{\circ} and m2=(5x4) \mathrm{m} \angle 2=(5 x-4)^{\circ} , then find the measure of 1 \angle 1 .\newlineAnswer:
  1. Set up equation: Supplementary angles add up to 180180 degrees. We can set up an equation where the sum of m/1m/_{1} and m/2m/_{2} is equal to 180180 degrees.\newlineCalculation: (5x6)+(5x4)=180(5x - 6) + (5x - 4) = 180
  2. Simplify equation: Combine like terms to simplify the equation.\newlineCalculation: 5x+5x64=1805x + 5x - 6 - 4 = 180\newline10x10=18010x - 10 = 180
  3. Isolate variable: Add 1010 to both sides of the equation to isolate the term with the variable xx.\newlineCalculation: 10x10+10=180+1010x - 10 + 10 = 180 + 10\newline10x=19010x = 190
  4. Solve for x: Divide both sides of the equation by 1010 to solve for x.\newlineCalculation: 10x10=19010\frac{10x}{10} = \frac{190}{10}\newlinex=19x = 19
  5. Find measure of angle: Now that we have the value of xx, we can find the measure of /1/_1 by substituting xx back into the expression for m/1m/_1.\newlineCalculation: m/1=(5x6)m/_1 = (5x - 6)\newlinem/1=(5×196)m/_1 = (5 \times 19 - 6)\newlinem/1=(956)m/_1 = (95 - 6)\newlinem/1=89m/_1 = 89 degrees

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