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Let’s check out your problem:
∠
1
\angle 1
∠1
and
∠
2
\angle 2
∠2
are
supplementary angles
. If
m
∠
1
=
(
3
x
−
30
)
∘
\mathrm{m} \angle 1=(3 x-30)^{\circ}
m
∠1
=
(
3
x
−
30
)
∘
and
m
∠
2
=
(
3
x
+
18
)
∘
\mathrm{m} \angle 2=(3 x+18)^{\circ}
m
∠2
=
(
3
x
+
18
)
∘
, then find the measure of
∠
2
\angle 2
∠2
.
\newline
Answer:
View step-by-step help
Home
Math Problems
Algebra 2
Transformations of functions
Full solution
Q.
∠
1
\angle 1
∠1
and
∠
2
\angle 2
∠2
are supplementary angles. If
m
∠
1
=
(
3
x
−
30
)
∘
\mathrm{m} \angle 1=(3 x-30)^{\circ}
m
∠1
=
(
3
x
−
30
)
∘
and
m
∠
2
=
(
3
x
+
18
)
∘
\mathrm{m} \angle 2=(3 x+18)^{\circ}
m
∠2
=
(
3
x
+
18
)
∘
, then find the measure of
∠
2
\angle 2
∠2
.
\newline
Answer:
Understand Relationship:
Understand the relationship between supplementary angles. Supplementary angles add up to
180
180
180
degrees.
Set Up Equation:
Set up the equation using the relationship between supplementary angles.
\newline
m
angle 1
+
m
angle 2
=
180
\frac{m}{\text{angle 1}} + \frac{m}{\text{angle 2}} = 180
angle 1
m
+
angle 2
m
=
180
degrees
\newline
(
3
x
−
30
)
+
(
3
x
+
18
)
=
180
(3x - 30) + (3x + 18) = 180
(
3
x
−
30
)
+
(
3
x
+
18
)
=
180
Combine and Solve:
Combine like terms and solve for
x
x
x
.
6
x
−
30
+
18
=
180
6x - 30 + 18 = 180
6
x
−
30
+
18
=
180
6
x
−
12
=
180
6x - 12 = 180
6
x
−
12
=
180
Isolate Term with x:
Add
12
12
12
to both sides of the equation to isolate the term with
x
x
x
.
\newline
6
x
−
12
+
12
=
180
+
12
6x - 12 + 12 = 180 + 12
6
x
−
12
+
12
=
180
+
12
\newline
6
x
=
192
6x = 192
6
x
=
192
Divide to Solve for
x
x
x
:
Divide both sides by
6
6
6
to solve for
x
x
x
.
6
x
6
=
192
6
\frac{6x}{6} = \frac{192}{6}
6
6
x
=
6
192
x
=
32
x = 32
x
=
32
Substitute Value of
x
x
x
:
Substitute the value of
x
x
x
back into the expression for
m
/
angle
2
m/\text{angle } 2
m
/
angle
2
to find its measure.
m
/
angle
2
=
3
x
+
18
m/\text{angle } 2 = 3x + 18
m
/
angle
2
=
3
x
+
18
m
/
angle
2
=
3
(
32
)
+
18
m/\text{angle } 2 = 3(32) + 18
m
/
angle
2
=
3
(
32
)
+
18
Perform Multiplication and Addition:
Perform the multiplication and addition to find the measure of angle
2
2
2
.
\newline
m
/
angle
2
=
96
+
18
m/\text{angle } 2 = 96 + 18
m
/
angle
2
=
96
+
18
\newline
m
/
angle
2
=
114
m/\text{angle } 2 = 114
m
/
angle
2
=
114
degrees
More problems from Transformations of functions
Question
Find
g
(
x
)
g(x)
g
(
x
)
, where
g
(
x
)
g(x)
g
(
x
)
is the reflection across the x-axis of
f
(
x
)
=
9
∣
x
+
2
∣
−
4
f(x)=9|x+2|-4
f
(
x
)
=
9∣
x
+
2∣
−
4
.
\newline
Choices:
\newline
(
A
)
g
(
x
)
=
9
∣
x
+
2
∣
−
4
]
\text{}(A)g(x) = 9|x+2| - 4\text{]}
(
A
)
g
(
x
)
=
9∣
x
+
2∣
−
4
]
\newline
(
B
)
g
(
x
)
=
9
∣
x
−
2
∣
−
4
]
\text{}(B)g(x) = 9|x-2| - 4\text{]}
(
B
)
g
(
x
)
=
9∣
x
−
2∣
−
4
]
\newline
(
C
)
g
(
x
)
=
−
9
∣
x
−
2
∣
+
4
]
\text{}(C)g(x)=-9|x-2| +4\text{]}
(
C
)
g
(
x
)
=
−
9∣
x
−
2∣
+
4
]
\newline
(D)
g
(
x
)
=
−
9
∣
x
+
2
∣
+
4
]
\text{(D)}g(x) = -9|x + 2| + 4\text{]}
(D)
g
(
x
)
=
−
9∣
x
+
2∣
+
4
]
Get tutor help
Posted 1 year ago
Question
What does the transformation
f
(
x
)
↦
f
(
x
−
4
)
f(x) \mapsto f(x - 4)
f
(
x
)
↦
f
(
x
−
4
)
do to the graph of
f
(
x
)
f(x)
f
(
x
)
?
\newline
Choices:
\newline
(A)
translates it
4
units right
\text{translates it } 4 \text{ units right}
translates it
4
units right
\newline
(B)
translates it
4
units down
\text{translates it } 4 \text{ units down}
translates it
4
units down
\newline
(C)
translates it
4
units left
\text{translates it } 4 \text{ units left}
translates it
4
units left
\newline
(D)
translates it
4
units up
\text{translates it } 4 \text{ units up}
translates it
4
units up
Get tutor help
Posted 1 year ago
Question
What does the transformation
f
(
x
)
↦
f
(
4
x
)
f(x) \mapsto f(4x)
f
(
x
)
↦
f
(
4
x
)
do to the graph of
f
(
x
)
f(x)
f
(
x
)
?
\newline
Choices:
\newline
[A] stretches it vertically
\newline
[B] stretches it horizontally
\newline
[C]shrinks it horizontally
\newline
[D]shrinks it vertically
Get tutor help
Posted 1 year ago
Question
Find
g
(
x
)
g(x)
g
(
x
)
, where
g
(
x
)
g(x)
g
(
x
)
is the translation
9
9
9
units down of
f
(
x
)
=
10
x
+
8
f(x) = 10x + 8
f
(
x
)
=
10
x
+
8
.
\newline
Choices:
\newline
(A)
g
(
x
)
=
10
x
−
82
g(x) = 10x - 82
g
(
x
)
=
10
x
−
82
\newline
(B)
g
(
x
)
=
10
x
+
98
g(x) = 10x + 98
g
(
x
)
=
10
x
+
98
\newline
(C)
g
(
x
)
=
10
x
−
1
g(x) = 10x - 1
g
(
x
)
=
10
x
−
1
\newline
(D)
g
(
x
)
=
10
x
+
17
g(x) = 10x + 17
g
(
x
)
=
10
x
+
17
Get tutor help
Posted 1 year ago
Question
What kind of transformation converts the graph of
f
(
x
)
=
−
3
x
2
−
4
f(x) = -3x^2 - 4
f
(
x
)
=
−
3
x
2
−
4
into the graph of
g
(
x
)
=
−
3
x
2
+
6
g(x) = -3x^2 + 6
g
(
x
)
=
−
3
x
2
+
6
?
\newline
Choices:
\newline
[A]translation 10 units up
\text{[A]translation 10 units up}
[A]translation 10 units up
\newline
[B]translation 10 units down
\text{[B]translation 10 units down}
[B]translation 10 units down
\newline
[C]translation 10 units left
\text{[C]translation 10 units left}
[C]translation 10 units left
\newline
[D]translation 10 units right
\text{[D]translation 10 units right}
[D]translation 10 units right
Get tutor help
Posted 1 year ago
Question
The parabola
y
=
x
2
y=x^{2}
y
=
x
2
is scaled vertically by a factor of
7
7
7
. What is the equation of the new parabola?
\newline
y
=
y=
y
=
Get tutor help
Posted 1 year ago
Question
The parabola
y
=
x
2
y=x^{2}
y
=
x
2
is shifted down by
6
6
6
units and to the right by
5
5
5
units.
\newline
What is the equation of the new parabola?
\newline
y
=
y=
y
=
Get tutor help
Posted 1 year ago
Question
The parabola
y
=
x
2
y=x^{2}
y
=
x
2
is shifted up by
2
2
2
units and to the right by
3
3
3
units.
\newline
What is the equation of the new parabola?
\newline
y
=
y=
y
=
Get tutor help
Posted 1 year ago
Question
The parabola
y
=
x
2
y=x^{2}
y
=
x
2
is reflected across the
x
x
x
-axis and then scaled vertically by a factor of
5
5
5
.
\newline
What is the equation of the new parabola?
\newline
y
=
□
y=\square
y
=
□
Get tutor help
Posted 1 year ago
Question
The parabola
y
=
x
2
y=x^{2}
y
=
x
2
is scaled vertically by a factor of
1
10
\frac{1}{10}
10
1
.
\newline
What is the equation of the new parabola?
\newline
y
=
y=
y
=
Get tutor help
Posted 1 year ago
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