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/_1 and 
/_2 are supplementary angles. If 
m/_1=(3x-30)^(@) and 
m/_2=(3x+18)^(@), then find the measure of 
/_2.
Answer:

1 \angle 1 and 2 \angle 2 are supplementary angles. If m1=(3x30) \mathrm{m} \angle 1=(3 x-30)^{\circ} and m2=(3x+18) \mathrm{m} \angle 2=(3 x+18)^{\circ} , then find the measure of 2 \angle 2 .\newlineAnswer:

Full solution

Q. 1 \angle 1 and 2 \angle 2 are supplementary angles. If m1=(3x30) \mathrm{m} \angle 1=(3 x-30)^{\circ} and m2=(3x+18) \mathrm{m} \angle 2=(3 x+18)^{\circ} , then find the measure of 2 \angle 2 .\newlineAnswer:
  1. Understand Relationship: Understand the relationship between supplementary angles. Supplementary angles add up to 180180 degrees.
  2. Set Up Equation: Set up the equation using the relationship between supplementary angles.\newlinemangle 1+mangle 2=180\frac{m}{\text{angle 1}} + \frac{m}{\text{angle 2}} = 180 degrees\newline(3x30)+(3x+18)=180(3x - 30) + (3x + 18) = 180
  3. Combine and Solve: Combine like terms and solve for xx.6x30+18=1806x - 30 + 18 = 1806x12=1806x - 12 = 180
  4. Isolate Term with x: Add 1212 to both sides of the equation to isolate the term with xx.\newline6x12+12=180+126x - 12 + 12 = 180 + 12\newline6x=1926x = 192
  5. Divide to Solve for xx: Divide both sides by 66 to solve for xx.6x6=1926\frac{6x}{6} = \frac{192}{6}x=32x = 32
  6. Substitute Value of xx: Substitute the value of xx back into the expression for m/angle 2m/\text{angle } 2 to find its measure.m/angle 2=3x+18m/\text{angle } 2 = 3x + 18m/angle 2=3(32)+18m/\text{angle } 2 = 3(32) + 18
  7. Perform Multiplication and Addition: Perform the multiplication and addition to find the measure of angle 22.\newlinem/angle 2=96+18m/\text{angle } 2 = 96 + 18\newlinem/angle 2=114m/\text{angle } 2 = 114 degrees

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