Solve. (1)/(3m^(2)-18 m)+(m^(2)+2m-3)/(3m^(2)-18 m)=((m-2))/(3m-18)

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Simplify Denominators: First, we need to simplify the denominators of both fractions. The denominator 3m^2 - 18m can be factored out by taking 3m common. 3m^2 - 18m = 3m(m - 6)Check for Typo: Now, let's look at the second part of the problem, which seems to have a typo. The expression ((m-2))/((3m)/(3)-18) is not clear. It seems like there might be a mistake in the transcription of the problem. However, if we assume that the denominator is meant to be the same as the first fraction, we can proceed with the simplification.Combine Numerators: Since the denominators of both fractions are the same, we can combine the numerators over the common denominator. So, we have: (1 + m^2 + 2m - 3) / (3m(m - 6))Simplify Numerator: Now, we simplify the numerator by combining like terms. 1 + m^2 + 2m - 3 = m^2 + 2m - 2Final Simplification: The simplified form of the expression is: (m^2 + 2m - 2) / (3m(m - 6))Check for Further Simplification: Finally, we check if the expression can be simplified further. The numerator and the denominator have no common factors, so this is the simplified form.

Solve. $\newline$ $\frac{1}{3 m^{2}-18 m}+\frac{m^{2}+2 m-3}{3 m^{2}-18 m}=\frac{(m-2)}{{3m}-18}$

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Solve.\newline13m2−18m+m2+2m−33m2−18m=(m−2)3m−18 \frac{1}{3 m^{2}-18 m}+\frac{m^{2}+2 m-3}{3 m^{2}-18 m}=\frac{(m-2)}{{3m}-18} 3m2−18m1​+3m2−18mm2+2m−3​=3m−18(m−2)​

Solve. $\newline$ $\frac{1}{3 m^{2}-18 m}+\frac{m^{2}+2 m-3}{3 m^{2}-18 m}=\frac{(m-2)}{{3m}-18}$