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(1(1))/(x-2y)-(1(1))/(4y-2x)+((1))/(3x-6y)

1(1)x2y1(1)4y2x+(1)3x6y \frac{1(1)}{x-2 y}-\frac{1(1)}{4 y-2 x}+\frac{(1)}{3 x-6 y}

Full solution

Q. 1(1)x2y1(1)4y2x+(1)3x6y \frac{1(1)}{x-2 y}-\frac{1(1)}{4 y-2 x}+\frac{(1)}{3 x-6 y}
  1. Identify Fractions: Identify the expressions to be combined and note that they are fractions that need a common denominator.
  2. Simplify Denominators: Recognize that the denominators (x2y)(x-2y), (4y2x)(4y-2x), and (3x6y)(3x-6y) can be simplified and made common. Notice that (4y2x)(4y-2x) is 1(x2y)-1(x-2y) multiplied by 22, and (3x6y)(3x-6y) is (x2y)(x-2y) multiplied by 33.
  3. Find LCD: Find the least common denominator (LCD) for the three fractions. The LCD for (x2y)(x-2y), 2(x2y)-2(x-2y), and 3(x2y)3(x-2y) is 6(x2y)6(x-2y).
  4. Rewrite with LCD: Rewrite each fraction with the common denominator 6(x2y)6(x-2y). The first fraction is already 1x2y\frac{1}{x-2y}, so it needs to be multiplied by 66\frac{6}{6} to get the common denominator. The second fraction is 12(x2y)\frac{1}{-2(x-2y)}, so it needs to be multiplied by 33\frac{-3}{-3} to get the common denominator. The third fraction is 13(x2y)\frac{1}{3(x-2y)}, so it needs to be multiplied by 22\frac{2}{2} to get the common denominator.
  5. Multiply by 11: Multiply each fraction by the appropriate form of 11 to get the common denominator:\newline(1x2y)×(66)=66(x2y)(\frac{1}{x-2y}) \times (\frac{6}{6}) = \frac{6}{6(x-2y)}\newline(14y2x)×(33)=36(x2y)(\frac{1}{4y-2x}) \times (\frac{-3}{-3}) = \frac{-3}{6(x-2y)}\newline(13x6y)×(22)=26(x2y)(\frac{1}{3x-6y}) \times (\frac{2}{2}) = \frac{2}{6(x-2y)}
  6. Combine Fractions: Combine the fractions now that they have a common denominator: 66(x2y)(36(x2y))+26(x2y)\frac{6}{6(x-2y)} - \left(-\frac{3}{6(x-2y)}\right) + \frac{2}{6(x-2y)}
  7. Add and Subtract Numerators: Add and subtract the numerators: 6(3)+2=6+3+2=116 - (-3) + 2 = 6 + 3 + 2 = 11
  8. Write Combined Fraction: Write the combined fraction with the common denominator: 116(x2y)\frac{11}{6(x-2y)}

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