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Precalculus
Find the magnitude of a three-dimensional vector
Find the coordinates of the vertex of the following parabola using graphing technology. Write your answer as an
(
x
,
y
)
(x, y)
(
x
,
y
)
point.
\newline
y
=
−
2
x
2
−
12
x
−
2
y=-2 x^{2}-12 x-2
y
=
−
2
x
2
−
12
x
−
2
\newline
Answer:
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Rewrite in simplest terms:
6
c
−
9
(
−
2
c
−
9
)
6 c-9(-2 c-9)
6
c
−
9
(
−
2
c
−
9
)
\newline
Answer:
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Let
f
(
x
)
=
2
cos
(
π
x
4
)
f(x)=2 \cos \left(\frac{\pi x}{4}\right)
f
(
x
)
=
2
cos
(
4
π
x
)
and
g
(
x
)
=
x
−
6
g(x)=x-6
g
(
x
)
=
x
−
6
.
\newline
Find the sum of the areas enclosed by the graphs of
f
f
f
and
g
g
g
between
x
=
4
x=4
x
=
4
and
x
=
8
x=8
x
=
8
.
\newline
Use a graphing calculator and round your answer to three decimal places.
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