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Math Problems
Calculus
Find the limit at a vertical asymptote of a rational function II
=
4
(
5
e
−
1
/
2
)
2
ln
(
e
−
1
/
2
)
=
4
(
5
e
−
1
/
2
)
2
□
2
=
□
e
□
\begin{array}{l}=4\left(5 e^{-1 / 2}\right)^{2} \ln \left(e^{-1 / 2}\right) \\ =4\left(5 e^{-1 / 2}\right)^{2} \frac{\square}{2}=\square e^{\square}\end{array}
=
4
(
5
e
−
1/2
)
2
ln
(
e
−
1/2
)
=
4
(
5
e
−
1/2
)
2
2
□
=
□
e
□
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Find the solution to the system of equations.
\newline
You can use the interactive graph below to find the solution.
\newline
{
−
7
x
−
2
y
=
14
6
x
+
6
y
=
18
x
=
\begin{array}{l} \left\{\begin{array}{l} -7 x-2 y=14 \\ 6 x+6 y=18 \end{array}\right. \\ x= \end{array}
{
−
7
x
−
2
y
=
14
6
x
+
6
y
=
18
x
=
\newline
y
=
y=
y
=
\newline
□
\square
□
\newline
y
y
y
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Based on the following calculator output, determine the population standard deviation of the dataset, rounding to the nearest
1
1
1
ooth if necessary.
\newline
1-Var-Stats
x
ˉ
=
106.142857143
Σ
x
=
743
Σ
x
2
=
80877
S
x
=
18.3160091307
σ
x
=
16.9573294008
n
=
7
minX
=
77
Q
1
=
91
M
e
d
2
=
107
Q
3
=
120
max
X
=
131
\begin{array}{l} \text { 1-Var-Stats } \\ \bar{x}=106.142857143 \\ \Sigma x=743 \\ \Sigma x^{2}=80877 \\ S x=18.3160091307 \\ \sigma x=16.9573294008 \\ n=7 \\ \operatorname{minX}=77 \\ \mathrm{Q}_{1}=91 \\ \mathrm{Med}^{2}=107 \\ \mathrm{Q}_{3}=120 \\ \max \mathrm{X}=131 \end{array}
1-Var-Stats
x
ˉ
=
106.142857143
Σ
x
=
743
Σ
x
2
=
80877
S
x
=
18.3160091307
σ
x
=
16.9573294008
n
=
7
minX
=
77
Q
1
=
91
Med
2
=
107
Q
3
=
120
max
X
=
131
\newline
Answer:
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